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Xelga [282]
3 years ago
7

Which value of x is a solution of the inequality 12x-14<61

Mathematics
1 answer:
pochemuha3 years ago
4 0

An inequality is solved by more than one value - usually an interval, or a union of intervals.

In this case, we have:

12x-14

Add 14 to both sides:

12x

Divide both sides by 12:

x

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jenny has 68 1/2 pages of her left to read. How many pages will she have left after she reads 26 1/6 pages?
jekas [21]

Answer:

42 1/3

Step-by-step explanation:

We subtract 26 1/6 from 68 1/2. We do this by finding the LCM of 6 and 2. That is 6. We multiply 1/2 by 3/3 to get 3/6. Now, we subtract. 68 - 26 is 42, and 3/6 - 1/6 is 2/6. Our answer is 42 2/6. That can be simplified to 42 1/3.

6 0
2 years ago
Hey:) can you please help me posted picture of question
oee [108]
Answer:
x² + 10x + 25

Explanation:
Before we begin, remember the following:
(a + b)(a + b) = (a + b)² = a² + 2ab + b²

Now, for the given we have:
(x + 5)(x + 5)
We can note that the two brackets are identical.
Therefore, we can apply the above rule as follows:
(x + 5)(x + 5) = (x + 5)²
                     = (x)² + 2(x)(5) + (5)²
                     = x² + 10x + 25

Hope this helps :)
8 0
3 years ago
I thought of a number. This number double is 7 less than 29. What is my number? hurry please
jekas [21]

Answer:

11

Step-by-step explanation:

11*2=22

29-7 =22

6 0
2 years ago
Read 2 more answers
What is the perimeter of a rectangle with a length of (x^2+x) and a width of (2x^2+3x)
Mazyrski [523]

Answer:

Perimeter = 6x² + 8x

Step-by-step explanation:

Perimeter = 2(length + width)

perimeter = 2((x²+x)+(2x²+3x))

perimeter = 2(x²+2x² + x+3x)

perimeter = 2(3x² + 4x)

perimeter = 2*3x² + 2*4x

perimeter = 6x² + 8x

5 0
3 years ago
HELP I attracted a picture????
posledela

Answer:

D. 187 m²

Step-by-step explanation:

Alrighty, so this is a standard area problem, the formula for finding the area of a triangle is base x height ÷ 2  so:

34 x 11 ÷ 2 = 187

So the area of the triangle is 187 m²

hope this helps:)

6 0
2 years ago
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