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Komok [63]
3 years ago
10

Part B: Quantitative

Physics
1 answer:
Feliz [49]3 years ago
4 0

Answer:

(a)

\triangle v=-8\ m/s\\\triangle mv=-56\ kg.m/s

(b)

5600 N

Explanation:

Change in velocity, \triangle v is expressed as

\triangle v= v_f -v_i

Where v represent the velocity and subscripts f and i represent final and initial respectively. Given that the ball finally comes to rest, its final velocity is taken as 0. Substituting 0 for final velocity and the given figure of 8 m/s for initial velocity then the change in velocity is given by

\triangle v=0-8=-8\ m/s

To find the change in momentum, m\triangle v then we substitute 7 kg for m and -8 m/s for \triangle v therefore \triangle\ v=7 Kg\times -8 m/s=-56\ Kg.m/s

(b)

The impact force, F is equivalent to ma where m is the mass of the ball and a is the acceleration. Here, acceleration is given by dividing the change in velocity by time ie

a=\frac {\triangle v}{t}=\frac { v_f -v_i}{t}

Substituting t with 0.05 s then a=\frac {\triangle v}{t}=\frac { v_f -v_i}{t}=\frac {-8}{0.01}=-800 m/s^{2}

Since F=ma then substituting m with 7 Kg we get that F=7*-800=-5600 N

Therefore, the impact force is equivalent to 5600 N

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An example of a balanced force would be a book sitting on a shelf untouched.

Isaac Newton’s First Law of Motion states that an object at motion stays in motion, and an object at rest stays at rest until acted on by an unbalanced force. A book sitting still is an example of a balanced force because nothing is acting on it; its potential energy is stored while it’s at rest. For this book to become an unbalanced force, an outside force would have to occur (i.e pushing the book or dropping it) that causes it to not be in a state of stillness.
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9 months ago
At the Earth's surface, a projectile is launched straight up at a speed of 10.0km / s. To what height will it rise? Ignore air r
icang [17]

At h = 5199.28 km  it will rise. Kinetic energy is a type of energy that is present in a particle or object in motion.

<h3>What is kinetic energy?</h3>

Kinetic energy is a type of energy that is present in a particle or object in motion. When work, which entails the transfer of energy, is done on an object by applying a net force, that object acquires kinetic energy.

There are five types of kinetic energy: mechanical, electrical, acoustic, thermal, and radiant. Kinetic energy (KE), which is the energy of a body in motion, is essentially the energy of all moving objects. It is one of the two main types of energy together with potential energy, which is the stored energy existing in objects at rest. 

<h3>To what height will it rise?</h3>

Equating the initial kinetic energy to the final potential energy

At the highest point, the body has only potential energy

initial kinetic energy = .5 * m * v2

velocity = 10.1 km/s

= 10.1 * 10100 m/s

= 10100 m/s

KE = .5 * m * (10100)2 = 51.005 x 106 x m   J

potential energy = m x g x h

max height reached = m x 9.81 x h

m x 9.81 x h =  51.005 x 106 x m   J

h = 5199.28 km

To learn more about kinetic energy, refer to:

brainly.com/question/25959744

#SPJ4

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What's an impure potassium carbonate
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Pearl Ash is an example of an Impure Potassium Carbonate 
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2 years ago
Virginia beach is 15 kilometers wide and 50 kilometers long. if 2 cm of rain falls on virginia beach, how many cubic meters of r
icang [17]
Assume that the shape of Virginia beach is rectangular.

Note that
1 km = 10³ m
1 cm = 10⁻² m

The area is
A = (15 km)*(50 km)
   = (15 x 10³ m)*(50 x 10³ m)
   = 7.5 x 10⁸ m²

Because 2 cm of rain fell, the volume is
V = (7.5 x 10⁸ m)*(2 x 10⁻² m) = 1.5 x 10⁶ m³

Answer:  1.5 x 10⁶ m³
4 0
3 years ago
A 2kg mass is moving at 3m/s. What is its kinetic energy?
Illusion [34]
<h2><u>KINETIC ENERGY</u></h2>

<h3>Problem:</h3>

» A 2kg mass is moving at 3m/s. What is its kinetic energy?

<h3>Answer:</h3>
  • \color{hotpink} \bold{9 \: J} \\

— — — — — — — — — —

<h3>Formula:</h3>

To calculate the velocity of a kinetic energy, we can use formula

  • \underline{ \boxed{  \tt KE =  \frac{1}{2} m{v}^{2}  } }

where,

  • v is the velocity in m/s
  • KE is the kinetic energy in J (joules)
  • m is the mass in kg

— — —

Based on the problem, the givens are:

  • KE (Kinetic energy) = ? (unknown)
  • m (mass) = 2 kg
  • v (velocity) = 3 m/s

<h3>Solution:</h3>

To get the velocity, substitute the givens in the formula above then solve.

\:   \: \tt KE =  \frac{1}{2} m{v}^{2}   \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: \tt \:   KE =  \frac{1}{2} \times  2 \times {(3)}^{2}  \\ \tt  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  KE =  \frac{1}{2}  \times(2\times 9) \\ \tt  KE =  \underline{ \boxed{ \blue{ \tt9 \: J}}}

Therefore, the kinetic energy is 9 Joules.

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1 year ago
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