Answer:
b liquids
Explanation:
this is because liquids take the shape of their container while solids stay solid and do not change shape and solids, liquids and gases all have definite volume.
Answer:
a) a = 4.57 m/s², b) a = 6.48 m / s²
, c) a = 1.42 m / s²,d) r = 82.3 m
Explanation:
The centripetal acceleration is the acceleration responsible for the change of direction of the acceleration vector and occurs in circular movements, the expression is
a = v² / r
let's apply this precaution to our cases
a) let's calculate
a = 8²/14
a = 4.57 m/s²
b) an automobile at v = 65 km / h (1000 m / 1km) (1 h / 3600 s) =18,055 m/s
let's reduce feet to meters
1 ft = 0.3048 m
r = 165 ft (0.3048 m / 1 ft) = 50.292 m
a = 18,055 2 / 50,292
a = 6.48 m / s²
c) we calculate
a = 1.25²2 / 1.1
a = 1.42 m / s²
d) we look for the radius
a = v² / r
r = v² / a
we reduce
v = 80 km / h (1000 m / 1km) (1h / 3600s) = 22.22 ms
r = 22.22²/6
r = 82.3 m
e) the cenripeta acceleration is used to take the curves on the highway,
Used in centrifuges to separate compounds
It is used in the games of the park of atraccio
Used in CD players and computer hard drives
Answer:
39.81 N
Explanation:
I attached an image of the free body diagrams I drew of crate #1 and #2.
Using these diagram, we can set up a system of equations for the sum of forces in the x and y direction.
∑Fₓ = maₓ
∑Fᵧ = maᵧ
Let's start with the free body diagram for crate #2. Let's set the positive direction on top and the negative direction on the bottom. We can see that the forces acting on crate #2 are in the y-direction, so let's use Newton's 2nd Law to write this equation:
- ∑Fᵧ = maᵧ
- T₁ - m₂g = m₂aᵧ
Note that the tension and acceleration are constant throughout the system since the string has a negligible mass. Therefore, we don't really need to write the subscripts under T and a, but I am doing so just so there is no confusion.
Let's solve for T in the equation...
- T₁ = m₂aᵧ + m₂g
- T₁ = m₂(a + g)
We'll come back to this equation later. Now let's go to the free body diagram for crate #1.
We want to solve for the forces in the x-direction now. Let's set the leftwards direction to be positive and the rightwards direction to be negative.
The normal force is equal to the x-component of the force of gravity.
- (F_n · μ_k) - m₁g sinΘ = m₁aₓ
- (F_g cosΘ · μ_k) - m₁g sinΘ = m₁aₓ
- [m₁g cos(30) · 0.28] - [m₁g sin(30)] = m₁aₓ
- [(6)(9.8)cos(30) · 0.28] - [(6)(9.8)sin(30)] = (6)aₓ
- [2.539595871] - [-58.0962595] = 6aₓ
- 60.63585537 = 6aₓ
- aₓ = 10.1059759 m/s²
Now let's go back to this equation:
We have 3 known variables and we can solve for the tension force.
- T = 2(10.1059759 + 9.8)
- T = 2(19.9059759)
- T = 39.8119518 N
The tension force is the same throughout the string, therefore, the tension in the string connecting M2 and M3 is 39.81 N.
Answer:
First law of motion
Explanation:
I say this because this example shows how an object is staying persistent unless it's compled to change
(not sure)