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belka [17]
4 years ago
8

How to get a + b on a graph

Physics
1 answer:
Nataly [62]4 years ago
3 0

The first positively essential requirement is that
you absolutely have to know what 'a' and 'b' are.

I have no clue, so this is as far as I can go.


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Anastasy [175]

Answer:

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Expansionary monetary policies would likely cause
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Answer:

TRUE

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Seasonal changes in water temperature tend to remain within a narrow range. This is opposed to air temperature, which tends to f
Serjik [45]

It is because of the high specific heat of water.

Specific heat is the amount of heat needed to change the temperature of unit mass of a substance by one degree.

Specific heat of water is 4.186 kJ/kg K and that of air is 1 kJ/kg K. Thus, a given amount of heat will cause more change in the temperature of air than that of water.

5 0
3 years ago
Read 2 more answers
A simple pendulum is used to measure gravity using the following theoretical equation,TT=2ππ�LL/gg ,where L is the length of the
Elina [12.6K]

Answer:

g ±Δg = (9.8 ± 0.2) m / s²

Explanation:

For the calculation of the acceleration of gravity they indicate the equation of the simple pendulum to use

          T = 2\pi  \sqrt{ \frac{L}{g} }

          T² =  4\pi ^2 \frac{L}{g}4pi2 L / g

          g = 4\pi ^2   \frac{L}{T^2}

They indicate the average time of 20 measurements 1,823 s, each with an oscillation

let's calculate the magnitude

           g = 4\pi ^2  \frac{0.823}{1.823^2}4 pi2 0.823 / 1.823 2

            g = 9.7766 m / s²

now let's look for the uncertainty of gravity, as it was obtained from an equation we can use the following error propagation

for the period

             T = t / n

             ΔT = \frac{dT}{dt} Δt + \frac{dT}{dn} ΔDn

In general, the number of oscillations is small, so we can assume that there are no errors, in this case the number of oscillations of n = 1, consequently

              ΔT = Δt / n

              ΔT = Δt

now let's look for the uncertainty of g

             Δg = \frac{dg}{dL} ΔL + \frac{dg}{dT}  ΔT

             Δg = 4\pi ^2 \frac{1}{T2}   ΔL + 4π²L  (-2  T⁻³) ΔT

           

a more manageable way is with the relative error

             \frac{\Delta g}{g}   = \frac{\Delta L }{L} + \frac{1}{2}  \frac{\Delta T}{T}

we substitute

              Δg = g ( \frac{\Delta L }{L} + \frac{1}{2}  \frac{\Delta T}{T}DL / L + ½ Dt / T)

the error in time give us the stanndard deviation  

let's calculate

               Δg = 9.7766 (\frac{0.001}{0.823} + \frac{1}{2}  \ \frac{0.671}{1.823})

               Δg = 9.7766 (0.001215 + 0.0184)

               Δg = 0.19 m / s²

the absolute uncertainty must be true to a significant figure

                Δg = 0.2 m / s2

therefore the correct result is

               g ±Δg = (9.8 ± 0.2) m / s²

5 0
3 years ago
At a given instant, the force on an electron is in the +z-direction (out of the page), which the electron is moving in the +x-di
Hitman42 [59]

Answer:

The direction of the B-field is in the +y-direction.

Explanation:

The corresponding formula is

F_B = qv\times B

This means, we should use right-hand rule.

Our index finger is pointed towards +x-direction (direction of velocity),

our middle finger should point towards the direction of the B-field,

and our thumb should point towards the +z-direction (direction of the force).

Since our middle finger in this situation points towards +y-direction, the B-field should be in +y-direction.

\^{x} \times \^{y} = \^{z}

3 0
4 years ago
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