Ask question

Ask question

All categories

3 years ago

11

A force of 30 N is applied to a screwdriver to pry the lid off of a can of paint. The screwdriver applies 75 N of force to the l

id. What is the mechanical advantage of the screwdriver?

1 answer:

Ipatiy [6.2K]3 years ago

7 0

The formula of mechanical advantage in this situation is:
MA = Input Force ÷ Output Force

The input force is the 30N applied to a screwdriver while the output force is the 75N force to the lid.

So,

MA = 30N/75N
MA = 0.40

Hence the mechanical advantage of the screwdriver is 0.40.

You might be interested in

Explain how materials are classified on the basis of electrical conductivity. Give two uses of these materials in day to day lif

vitfil [10]

Answer: On the basis of electrical conductivity, materials are classified as conductors, semi-conductors and non-conductors. Conductors : Substances through which electricity can easily pass through are known as conductors. ... For example, glass, wood are non-conductors. Wood is used to make tables, desks etc.

3 0

2 years ago

Name two things in the lab that are for safety

Blizzard [7]

Answer:

Safety goggles and chemical fume hoods

Explanation:

5 0

3 years ago

#5.) Explain why the rock cycle is referred to as a "cycle".

Natalka [10]

The rock cycle is referred to as cycle because it repeats over and over again. The definition of cycle is a series of events that are regularly related in the same order. So with the rock cycle they stay in the same order and repeat.
Hope this helps :)

5 0

3 years ago

Read 2 more answers

Calculate the speed of a dog running through a field if he is covering 23.7 meters in 54 seconds.

Elenna [48]

Explanation:

speed = distance/time

= 23.7/54 m/s

= 0.44 m/s

speed of a dog running through a field = 0.44 m/s

4 0

3 years ago

Read 2 more answers

The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C

avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

$q=c\times (T_{final}-T_{initial})$

where,

q = heat gained = ?

c = specific heat = $5.20kJ/^oC$

$T_{final}$ = final temperature = $27.43^oC$

$T_{initial}$ = initial temperature = $22.93^oC$

Now put all the given values in the above formula, we get:

$q=5.20kJ/^oC\times (27.43-22.93)^oC$

$q=23.4kJ$

Now we have to calculate the enthalpy change during the reaction.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = $\frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole$

$\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole$

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

$\Delta H=\Delta U+\Delta n_gRT$

or,

$\Delta U=\Delta H-\Delta n_gRT$

where,

$\Delta H$ = change in enthalpy = $-2805.8kJ/mol$

$\Delta U$ = change in internal energy = ?

$\Delta n_g$ = change in moles = 0 (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = $27.43^oC=273+27.43=300.43K$

Now put all the given values in the above formula, we get:

$\Delta U=\Delta H-\Delta n_gRT$

$\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K$

$\Delta U=-2805.8kJ/mol-0$

$\Delta U=-2805.8kJ/mol$

Therefore, the internal energy change is -2805.8 kJ/mol

5 0

3 years ago