Ask question

Ask question

All categories

3 years ago

11

A force of 30 N is applied to a screwdriver to pry the lid off of a can of paint. The screwdriver applies 75 N of force to the l

id. What is the mechanical advantage of the screwdriver?

1 answer:

Ipatiy [6.2K]3 years ago

7 0

The formula of mechanical advantage in this situation is:
MA = Input Force ÷ Output Force

The input force is the 30N applied to a screwdriver while the output force is the 75N force to the lid.

So,

MA = 30N/75N
MA = 0.40

Hence the mechanical advantage of the screwdriver is 0.40.

You might be interested in

What kind of chemical bonds are represented by the product in the following diagram?

katovenus [111]

The chemical bonds in CH4 are all single bonds. C only can bond 4 times because it needs 8 electrons in it's outer shell and only has four right now. The bonds represented are all single bonds because there are two electrons present on each side of the carbon. Two electrons, in this case, equals one bond.

4 0

3 years ago

Etyl axetat có công thức là

mina [271]

I like people who are short and know what”a popppppppp

8 0

3 years ago

3. Crystalline structural unit of barium metal is a body-centered cubic cell. The edge length of the unit cell is 5.02x10-8 cm.

tiny-mole [99]

Answer:

The Avogadro's number is $N_A = 6.02289 *10^{23}$

Explanation:

From the question we are told that

The edge length is $L = 5.02 * 10^{-8} \ cm= \frac{5.02 * 10^{-8} }{100} = 5.02 * 10^{-10}$

The density of the metal is $\rho = 5.30\ g/cm^3 = 5.30 * \frac{g}{cm^3} * \frac{1*10^6}{1*10^3} = 5.30 *10^3kg/m^3$

The molar mass of Ba is $Z = 137.3 \ g/mol = \frac{137.3}{1000} = 0.1373 \ kg / mol$

Generally the volume of a unit cell is

$V = L^3$

substituting value

$V = [5.02 *10^{-10}]^3$

$V = 1.265*10^{-28}\ m^3$

From the question we are told that 68% of the unit cell is occupied by Ba atoms and that the structure is a metal which implies that the crystalline structure will be (BCC),

The volume of barium atom is

$V_a = \frac{V}{2} * 0.68$

substituting value

$V_a = \frac{ 1.265*10^{-28}}{2} * 0.68$

$V_a = 4.301 *10^{-29} \ m^3$

The Molar mass of barium is mathematically represented as

$Z = N_A V_a * \rho$

Where $N_A$ is the Avogadro's number

So

$N_A = \frac{ Z}{ V_a * \rho}$

substituting value

$N_A = \frac{ 0.1373}{ 4.301*10^{-29} * 5.3*10^{3}}$

$N_A = 6.02289 *10^{23}$

4 0

3 years ago

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibrium described by the equation N2O4(g)

Tresset [83]

Answer : The equilibrium constant $K_c$ for the reaction is, 0.869

Explanation :

First we have to calculate the concentration of $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

The balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initial conc. C 0

At eqm. conc. $(C-C\alpha)$ $(2C\alpha)$

As we are given,

The percent of dissociation = $\alpha$ = 37 % = 0.37

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(2C\alpha)^2}{(C-C\alpha)}$

Now put all the values in this expression, we get :

$K_c=\frac{(2\times 1.0\times 0.37)^2}{(1.0-1.0\times 0.37)}$

$K_c=0.869$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.869

3 0

3 years ago

Which properties change the composition of a substance? A physical properties

Ugo [173]

The correct answer is B.

8 0

3 years ago

Read 2 more answers