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Shkiper50 [21]
3 years ago
8

When using the right-hand rule to determine the direction of the magnetic field around a current-carrying wire, which part of th

e
right hand points in the direction of the magnetic field?

-palm
-fingers
-back
-thumb
Physics
2 answers:
geniusboy [140]3 years ago
7 0

Answer: Palm

Explanation: When you have a wire, you must point your thumb in the direction in which the electricity is going, and now you close your palm, in the direction in which you closed your hand is in the direction in which points the magnetic field.

Then the correct option is the first one, the palm points in the direction of the magnetic field.

mezya [45]3 years ago
6 0

Answer:

Fingers

Explanation:

The index finger shows the moving charge, while your middle finger shows the magnetic field line.

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PLEASE ASAP GIVING BRAINLIEST!!!
kakasveta [241]

Answer:

x=14

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3 years ago
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A ball is projected upward at time t=0.0s, from a point on a roof 90m above the ground. The ball rises, then falls and strikes t
chubhunter [2.5K]
As v becomes zero at the highest point, i prefer considering different travelling directions so it will become less complicated.
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3 years ago
Which distance measurement is the most precise?
andrew-mc [135]
The distance that is measured in the most accurate manner is letter c. This is because centimeters is the smallest unit of measurement. The given choices show that the first two measurements are expressed with decimal places but the graduations of each are greater compared to centimeters. 
7 0
3 years ago
A particle is confined between rigid walls separated by a distance L = 0.167 nm. The particle is in the second excited state (n
ZanzabumX [31]

Answer:

The answer for a classical particle is 0.00595

Explanation:

The equation of the wave function of a particle in a box in the second excited state equals:

ψ(x) = ((2/L)^1/2) * sin((3*pi*x)/L)

The probability is equal to:

P(x)dx = (|ψ(x)|^2)dx = ((2/L)^1/2) * sin((3*pi*x)/L) = (2/L) * sin^2((3*pi*x)/L) dx

for x = 0.166 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.166)/0.167) * 100 pm = 0.037x10^-3

for x = 0.028 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.028)/0.167) * 100 pm = 11x10^-3

for x = 0.067 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.067)/0.167) * 100 pm = 3.99x10^-3

therefore, the classical probability is equal to:

(1/L)dx = (1/0.167)*100 pm = 0.00595

8 0
4 years ago
Alice and Bob sit on a see saw, that consists of a uniform beam of mass 20kg and a fulcrum rock, that acts as a pivot point. The
tankabanditka [31]

Answer:

Explanation:

Given

Mass of alice M_a=50 kg

Mass of bob M_b=70 kg

Mass of beam M=20 kg

Suppose fulcrum is at distance of d from bob thus From diagram

Equating torque i.e. torque of Bob,Alice and beam must cancel out each other to be balanced

500\times (8-d)+20\times (4-d)=70\times d

400-50d+80-2d=70d

480=140d

d=\frac{480}{140}

d=3.43 m    

5 0
4 years ago
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