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3 years ago

the equation of straight line passing through the point (2,3)&perpendicular to the line 4x-3y=10 is

Mathematics

1 answer:

fgiga [73]3 years ago

7 0

Answer:

4y = -3x +18

Step-by-step explanation:

Let's get the gradient from this line equation first.

4x-3y=10

4x-10=3y

Y= 4/3x -10/3

The gradient is 4/3.

For a line perpendicular to another line.

M*M'= -1

M= -/(4/3)

M = -3/4

So the gradient to be used is -3/4

Formula for solving is

(Y-y1)/(x-x1)= M

X1= 2

Y1= 3

M = -3/4

(Y-y1)/(x-x1)= M

(Y-3)/(x-2)= -3/4

4(y-3)= -3(x-2)

4y -12 = -3x +6

4y = -3x +18

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If the length of each side of an equilateral triangle were increased by 50 percent, what would be the percent increase in the ar

Shkiper50 [21]

Answer:

The area increase by 225%

Step-by-step explanation:

attachment of a triangle

The area of a triangle equilateral is calculated with the next formula:

A= $\frac{a*h}{2}$

$h^{2} +(\frac{a}{2})^{2}$ = $a^{2}$

$h^{2} = a^{2} - \frac{a^{2} }{4}$ = $\frac{a^{2} }{4}$ *3

h= $\sqrt{\frac{a^{2}*3 }{4} }$

h= $\frac{\sqrt{3}*a }{2}$

replacing in the A equation:

A= $\frac{a*\sqrt{3}*a }{2*2}$ 

A= $\frac{\sqrt{3}*a^{2} }{4}$ 

Now each side increse by 50% ⇒ a=1.5a

A= $\frac{\sqrt{3}*(1.5a)^{2} }{4}$ 

A= $\frac{\sqrt{3}*a^{2}* 2.25 }{4}$ 

A=2.25 * $\frac{\sqrt{3}*a^{2} }{4}$ 

It means that the area incrase by 225%

6 0

4 years ago

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vivado [14]

Answer:

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Step-by-step explanation:

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3 years ago

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Xelga [282]

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3 years ago

At a cafe, for every 8 hot dogs sold there are 11 hamburgers sold. What is the ratio of hot dogs sold to hamburgers sold?

Bezzdna [24]

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3 years ago

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Sladkaya [172]

Answer:

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I can't give you a very good explanation because I'm

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4 0

3 years ago

the equation of straight line passing through the point (2,3)&perpendicular to the line 4x-3y=10 is​

the equation of straight line passing through the point (2,3)&perpendicular to the line 4x-3y=10 is