All categories

3 years ago

Whts X+y x 9 +3 +4 ?

Mathematics

1 answer:

babunello [35]3 years ago

6 0

Expression simplified: $x+9y+7$

Step-by-step explanation:

The expression that we have in this problem is:

$x+y\cdot 9 +3 +4$

The first type of operation that we have to solve in such expression are multiplication/division.

In this expression, there is only one multiplication, that is:

$y\cdot 9 = 9y$

So we can rewrite the expression as

$x+9y+3+4$

Now we can evaluate the sum of the similar terms: in this case, similar terms are only 3 and 4, and their sum is

$3+4=7$

Therefore, the expression can be rewritten as

$x+9y+7$

Learn more about simplifying expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

You might be interested in

This for whoever wants to get 15 points for free.......Your welcome

Kobotan [32]

Answer:THANK YOUUUUUUU

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

How to solve (2x+8)^2

dusya [7]

You have to foil out the problem
(2x+8)(2x+8)
4x^2+16x+16x+64
4x^2+32x+64

4 0

3 years ago

Can someone please help me with math?

Fofino [41]

You most likely will win a token. you have the advantage as the most they can win is 1 token if you lose, but you can win 3 tokens.

6 0

3 years ago

The equation X squared plus Y squared minus 2X plus 7Y +1 equals zero can be written as which of the following equations

ad-work [718]

For this case we must write in algebraic symbology the expression described above:

We have an equation, then:

x squared plus y squared: $x ^ 2 + y ^ 2$

minus 2x plus 7y plus 1: $-2x + 7y + 1$

equals zero: $= 0$

We construct the equation:

$x ^ 2 + y ^ 2-2x + 7y + 1 = 0$

Answer:

$x ^ 2 + y ^ 2-2x + 7y + 1 = 0$

6 0

3 years ago

50 POINTS!!!

Goryan [66]

9514 1404 393

Answer:

f(x) = x
g(x) = -2x+1
f(x) -(-g(x)) = -x+1
f(x) +g(x) = -x+1
f(x)-(-g(x)) = (f+g)(x) is true for all functions f and g, linear or not

Step-by-step explanation:

We can define a couple of linear functions as ...

f(x) = x

g(x) = -2x+1

Then the reflected function -g(x) is ...

-g(x) = -(-2x +1) = 2x -1

And the difference from f(x) is ...

f(x) -(-g(x)) = x -(2x -1) = -x +1 . . . . f(x) -(-g(x))

We want to compare that to the sum of the functions:

f(x) +g(x) = x +(-2x +1) = -x +1 . . . . f(x) +g(x)

The two versions of the function expression have the same value.

These results are <em>a property of addition</em>, so do not depend on the nature of f(x) or g(x). They will hold for every function.

3 0

2 years ago