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Ronch [10]
4 years ago
14

How is the answer C?​

Physics
1 answer:
Lyrx [107]4 years ago
6 0

Explanation:

first the rocket is moving quicker and quicker so KE increases and momentum is the same as it would be then constant before the explosion

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In a home stereo system, low sound frequencies are handled by large "woofer" speakers, and high frequencies by smaller "tweeter"
Hitman42 [59]

Answer:

C = 2.9 10⁻⁵ F = 29 μF

Explanation:

In this exercise we must use that the voltage is

          V = i X

          i = V/X    

where X is the impedance of the system

in this case they ask us to treat the system as an RLC circuit in this case therefore the impedance is

          X = \sqrt{R^2 + ( wL - \frac{1}{wC})^2 }

tells us to take inductance L = 0.

The angular velocity is

         w = 2π f

the current is required to be half the current at high frequency.

Let's analyze the situation at high frequency (high angular velocity) the capacitive impedance is very small

         \frac{1}{wC} →0       when w → ∞

therefore in this frequency regime

         X₀ = \sqrt{R^2 + ( \frac{1}{2\pi  2 10^4 C} )^2 } =  R  \sqrt{ 1+ \frac{8 \ 10^{-10} }{RC}     }

the very small fraction for which we can despise it

        X₀ = R

to halve the current at f = 200 H, from equation 1 we obtain

         X = 2X₀

let's write the two equations of inductance

          X₀ = R                                    w → ∞

          X= 2X₀ = \sqrt{R^2 +( \frac{1}{wC} )^2 }        w = 2π 200

 

         

we solve the system

         2R = \sqrt{R^2 +( \frac{1}{wC} )^2 }

         4 R² = R² + 1 / (wC) ²

         1 / (wC) ² = 3 R²

          w C = \frac{1}{\sqrt{3} } \ \frac{1}{R}

          C = \frac{1}{\sqrt{3} } \ \frac{1}{wR}

           

let's calculate

           C = \frac{1}{\sqrt{3} } \ \frac{1}{2\pi  \ 200 \ 9}

           C = 2.9 10⁻⁵ F

           C = 29 μF

7 0
3 years ago
8. The emission by a body of visible light caused by a high temperature called ________.
Lorico [155]

Answer:

Luminescence

Explanation:

5 0
3 years ago
The first motor abilities a new born exhibits are
Arisa [49]

Answer:

here your answer

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5 0
3 years ago
What do you mean by momentum.Explain​
r-ruslan [8.4K]
Momentum is the quantity of moving motion if that helps in anyway :)
8 0
3 years ago
Read 2 more answers
A diffraction grating with 600 lines/mmlines/mm is illuminated with light of wavelength 510 nmnm. A very wide viewing screen is
Ksenya-84 [330]

Answer:

A.2.95 m

B.7

Explanation:

We are given that

Diffraction grating=600 lines/mm

d=\frac{1 mm}{600}=\frac{1\times 10^{-3} m}{600}=1.67\times 10^{-6} m

Wavelength of light,\lambda=510 nm=510\times 10^{-9} m

l=4.6 m

A.We have to find the distance between the two m=1 bright fringes

sin\theta=\frac{m\lambda}{d}

For first bright fringe, =1

sin\theta=\frac{1\times 510\times 10^{-9}}{1.67\times 10^{-6}}=0.305

\theta=sin^{-1}(0.305)=17.76^{\circ}

The distance between two m=1 fringes

x=2ltan\theta=2\times 4.6 tan(17.76^{\circ})=2.95 m

Hence, the distance between two m=1 fringes=2.95 m

B.For maximum number of fringes,

sin\theta=1

sin\theta=\frac{m\lambda}{d}

Substitute the values

1=\frac{m\times 510\times 10^{-9}}{1.67\times 10^{-6}}

m=\frac{1.67\times 10^{-6}}{510\times 10^{-9}}=3.3\approx 3

Maximum number of bright fringes on the scree=2m+1=2(3)+1=7

8 0
4 years ago
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