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attashe74 [19]
3 years ago
13

An organ pipe is open at both ends. It is producing sound

Physics
1 answer:
ozzi3 years ago
3 0

To solve this problem we will apply the concepts related to the wavelength of its third harmonic.

It describes that the wavelength is equivalent to

\lambda = \frac{2}{3}L

Here,

\lambda = Wavelength

The wavelength is in turn described as a function that depends on the change of the speed as a function of the frequency, that is to say

\lambda = \frac{v}{f}

In this case the speed is equivalent to the speed of sound and the frequency was previously given, therefore

\lambda = \frac{343}{262}

\lambda = 1.3091m

Finally the length of the pipe would be

L= \frac{3}{2}(1.3091)

L = 1.963m

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Which observational tool helped astronomers Arno Penzias and Robert Wilson discover the
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2 years ago
Read 2 more answers
When a tuning fork vibrates over an open pipe and the air in the pipe starts to vibrate, the vibrations in the tube are caused b
defon

Answer:

correct option is A. Resonance

Explanation:

solution

vibrations in the tube are caused by the Resonance because Resonance cause of sounds production in the musical instrument

As if resonance ( hollow cylindrical tube) immerse in  cylinder of water and force in to vibration by tuning fork

As tines of tuning fork vibrate at natural frequency and it create sound wave that impinged up on opening of resonance tube

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8 0
3 years ago
A force of 14 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work W is done in stretching i
enyata [817]

Answer:

W = 19.8 J

Explanation:

14 lb force is required to stretch the spring by 4 inch distance

So we have

F = 14 lbf

F = 6.35 \times 9.8 N

F = 62.3 N

stretch in the spring is given as

x = 4 in = 0.1016 m

now we will have

F = kx

62.3 = k(0.1016)

k = 613.125 N/m

Now we need to find the work to stretch it by x = 10 in = 0.254 m

so we have

W = \frac{1}{2}kx^2

W = \frac{1}{2}(613.125)(0.254)^2

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3 years ago
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