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attashe74 [19]
3 years ago
13

An organ pipe is open at both ends. It is producing sound

Physics
1 answer:
ozzi3 years ago
3 0

To solve this problem we will apply the concepts related to the wavelength of its third harmonic.

It describes that the wavelength is equivalent to

\lambda = \frac{2}{3}L

Here,

\lambda = Wavelength

The wavelength is in turn described as a function that depends on the change of the speed as a function of the frequency, that is to say

\lambda = \frac{v}{f}

In this case the speed is equivalent to the speed of sound and the frequency was previously given, therefore

\lambda = \frac{343}{262}

\lambda = 1.3091m

Finally the length of the pipe would be

L= \frac{3}{2}(1.3091)

L = 1.963m

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Urgently!
adelina 88 [10]

Answer:

0.003333 s to 0.000125s or from 3.33ms to 0.125ms wher m is for milli

1.1m to 0.04125 m

Explanation:

T= 1/f=

if f= 300Hz then T = 1/300 =0.003333 s

if f= 8000 then T= 1/8000 = 0.000125s

now v=f×wave length

or wavelength = speed/ frequency

when f = 300 Hz

wavelength = 330/300=1.1 m

wavelength = 330/8000 = 0.04125m

note : i have taken speed of sound as 330 m/s you can take any value given in between 330m/s to 340m/s

6 0
3 years ago
A force Fof 40000 lbf is applied to rod AC the negative Y-direction. The rod is 1000 inches tall. A Force P of 25 lbf is applied
erastova [34]

Answer:

The answer is "effective stress at point B is 7382 ksi "

Explanation:

Calculating the value of Compressive Axial Stress:

\to \sigma y  =\frac{F}{A} = \frac{4 F}{( p d ^2 )} = \frac{(4 x ( - 40000 \ lbf))}{[ p \times (1 \ in)^2 ]} = - 50.9 \ ksi \\

Calculating Shear Transverse:

\to \frac{4v}{ 3 A} = \frac{4 (75 \ lbf + 25 \ lbf)}{ \frac{3 ( lni)^2}{4}}

        = \frac{4 (100 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\ = \frac{400 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\= 0.17 \ ksi

= R \times 200 \ in - P \times 100 \ in = 12500 \ lbf \times\  in

\to \sigma' =[ s y^2 +3( t \times y^2 + t yz^2 )] \times \frac{1}{2}\\\\

       = [ (-50.9)^2 +3((63.7)^2 +(0.17)^2 )] \times \frac{1}{2}\\\\=[2590.81+ 3(4057.69)+0.0289]\times \frac{1}{2}\\\\=[2590.81+12,173.07+0.0289] \times \frac{1}{2}\\\\=14763.9089\times \frac{1}{2}\\\\ = 7381.95445 \ ksi\\\\ = 7382 \ ksi

8 0
3 years ago
Which fact is true during a fission chain reaction?
Free_Kalibri [48]

Answer:

The number of freely-moving neutrons decreases over time.

The number of freely-moving neutrons decreases over time.

Explanation:

8 0
3 years ago
I need help on this question!
Mashutka [201]

Explanation:

click the link you can get answer of the question

3 0
3 years ago
Sound waves with frequency higher that 20,000 Hz are referred to as
Solnce55 [7]
<span>Sound waves with frequency higher that 20,000 Hz are referred to as "Ultrasonic"

Hope this helps!</span>
4 0
3 years ago
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