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3 years ago

An organ pipe is open at both ends. It is producing sound

Physics

1 answer:

ozzi3 years ago

3 0

To solve this problem we will apply the concepts related to the wavelength of its third harmonic.

It describes that the wavelength is equivalent to

$\lambda = \frac{2}{3}L$

Here,

$\lambda = Wavelength$

The wavelength is in turn described as a function that depends on the change of the speed as a function of the frequency, that is to say

$\lambda = \frac{v}{f}$

In this case the speed is equivalent to the speed of sound and the frequency was previously given, therefore

$\lambda = \frac{343}{262}$

$\lambda = 1.3091m$

Finally the length of the pipe would be

$L= \frac{3}{2}(1.3091)$

$L = 1.963m$

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Explanation:

Problem 1

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The builder's equation

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R₁ > 0

Cas2 Flat-concave (divergent) lens

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Why the correct answers are iii and iv

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1 / i = 1 / f₂ - 1 / (L-f₁)

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i = f₂ (L-f₁) / (L - (f₁ + f₂))

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