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KATRIN_1 [288]
4 years ago
7

Touching your finger to your nose, action force?

Physics
1 answer:
blsea [12.9K]4 years ago
5 0
Yes  i think since action force means moving in one direction 
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Two electric charges, held a distance, d, apart experience an electric force of magnitude, F, between them. If one of the charge
Aneli [31]

Answer:

When one of charge is doubled, the magnitude of the force between them gets doubled.

Explanation:

The electric force between two electric charges is given by :

F=k\dfrac{q_1q_2}{d^2}

Here,

k is the electrostatic force

d is the separation between charges

q_1\ and\ q_2 are charges

If one of the charges is doubled in magnitude while maintaining the same separation between the charges, q_1'=2q_1

New force becomes,

F'=k\dfrac{q_1'q_2'}{d'^2}

F'=k\dfrac{(2q_1)q_2'}{d'^2}

F'=2k\dfrac{q_1q_2'}{d'^2}

When one of charge is doubled, the magnitude of the force between them gets doubled. Hence, this is the required solution.

7 0
4 years ago
You travel in a circle, whose circumference is 8kilometers, at an average speed of kilometer/hour. If you stop at the same point
dimaraw [331]

You skipped over a number in the question, and you didn't tell me what my average speed is. Lucky for you, my average speed has NO EFFECT on the answer to the question.

When you calculate velocity, you only use the straight-line distance between the start-point and the end-point. It doesn't matter what route the thing took to get there, or how much ground it actually covered.

If I travel in a circle and stop at the same point I started from, then the size of the circle doesn't matter, and neither does my speed. The distance between my start-point and my end-point is zero, and my average velocity is zero.

3 0
4 years ago
A steel wire of length 1.5 m and diameter 1 mm is joined to an aluminum wire of identical dimensions to make a composite wire of
Anarel [89]

Answer:

1.805 mm

Explanation:

Extension in the steel wire = WL_{steel}/AE_{steel}

Extension in the aluminium wire = WL_{Al}/AE_{Al}

Total extension = W/A * (L_{steel}/E_{steel} + L_{Al}/E_{Al})

we have:

W = mg

W = 5 × 9.8

W = 49 N

Area A = π/4 × (0.001)²

= 7.85398 × 10 ⁻⁷ m²

Total extension = W/A * (L_{steel}/E_{steel} + L_{Al}/E_{Al})

Total extension = 49/ 7.85398 × 10 ⁻⁷ ( (1.5/ 200×10⁹) + 1.5/ 70×10⁹))

Total extension =  0.0018048

Total extension = 1.805 mm

Thus, the total extension = the resulting change in the length of this composite wire = 1.805 mm

4 0
3 years ago
20 waves crash onto a beach every 57.1 s. what is their frequency? answer in units of hz.
Andrei [34K]
20waves/57.1s = 0.350 Hz
thank you!
8 0
3 years ago
1. what factor does work depends on?<br>2. what factor does power depends on? ​
Harrizon [31]
1.motivation 2. ????
5 0
3 years ago
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