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Alex777 [14]
3 years ago
11

Consider an electric dipole, composed of charges +q and -q separated by distance d, that is viewed from a large distance (large

compared to d). What do we expect about the electric field due to the dipole viewed from this distance?
A. The electric field could be weaker or stronger than a single point charge q viewed from the same distance.B. The electric field is significantly weaker than the electric field due to a single point charge q viewed from the same distance.C. The electric field is significantly stronger than a single point charge q viewed from the same distance.D. The electric field will be exactly zero.
Physics
1 answer:
Sidana [21]3 years ago
5 0

I tidy up the question as follows (Please notify me for any mistakes in the question):

Consider an electric dipole, composed of charges +q and -q separated by distance d, that is viewed from a large distance (large compared to d). What do we expect about the electric field due to the dipole viewed from this distance?

A. The electric field could be weaker or stronger than a single point charge q viewed from the same distance.

B. The electric field is significantly weaker than the electric field due to a single point charge q viewed from the same distance.

C. The electric field is significantly stronger than a single point charge q viewed from the same distance.

D. The electric field will be exactly zero.

Answer:

C) The electric field is significantly stronger than a single point charge q viewed from the same distance.

Explanation:

Electric field strength for single point charge is governed by the following equation:

E = kq/(r^2)

By having two electric dipole positive and negative, at any space between the dipoles, it will experience attraction and repulsion at the same time resulting the superposition of forces between the two forces.

Since both of the forces will be acting to the same way, the forces will be added.

Since force is proportional to energy, the electrical potential energy or in this case electric field will become significantly stronger.

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A 10-turn ideal solenoid has an inductance of 4. 0 mh. to generate an emf of 2. 0 v the current should change at a rate of:_____
Lady bird [3.3K]

The answer is 500 A/sec.

N=10 ; Solensid; L=4 m H ; \varepsilon=2 \mathrm{~V};

\begin{aligned}&\varepsilon=-L \frac{d I}{d t}=N \phi ; \\&2 \times \frac{1}{L}=-\frac{d I}{d t} ; \\&2 \times \frac{1}{4 \times 10^{-3}}=-\frac{d I}{d t} ;\end{aligned}

0.5 \times 10^{3}=\frac{d I}{dt}

So, 500 A/sec.

What is Solensid?

  • Electromagnets are magnets in which the wire is coiled around an iron core. When an electric current is applied to the iron core, a magnetic field is formed around it. When the power is turned off, the magnetic field dissipates. The wire-wound core of the magnet is ferromagnetic or ferrimagnetic in nature. The most prevalent material utilised in the core is iron.
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To learn more about Solensid visit:

brainly.com/question/15061394

#SPJ4

4 0
2 years ago
Find the acceleration of the system and the tension in the ropes for the system shown. The table mass is 30 kg and the hanging m
marusya05 [52]

The system's tension is 616 N and acceleration is 5.6 m / s^{2}

<u>Explanation:</u>

From newton’s second law of motion which state that net force acting on a body is product of mass of a body and acceleration of a body which is given as,

             F_{n e t}=m_{t o t} \times a

Where,

F_{n e t} is net force acting on body

m_{\mathrm{tot}} is mass of body

a is acceleration of body

Given values  

Table mass (m) = 30 kg

Hanging mass (m) = 40 kg

                a=\frac{F_{n e t}}{m_{\mathrm{tot}}}=\frac{m \times g}{m_{\mathrm{tot}}}

Put the value for m = hanging mass = 40 kg and g=9.8 \mathrm{m} / \mathrm{s}^{2}, we get

                  a=\frac{40 \times 9.8}{30+40}=\frac{392}{70}=5.6 \mathrm{m} / \mathrm{s}^{2}

The tension in the ropes,  T=(m \times g)+(m \times a)

Here, m as hanging mass

T = tension, N or  k g m / s^{2}

m = mass, kg  

g = gravitational force, 9.8 \mathrm{m} / \mathrm{s}^{2}

a = acceleration, m / s^{2}

          T = (40 \times 9.8)+(40 \times 5.6) = 392+224 = 616 N

3 0
3 years ago
After landing on an unexplored Klingon planet, Spock tests for the direction of the magnetic field by firing a beam of electrons
BARSIC [14]

Answer:

Magnetic field is in south west direction .

Explanation:

Let us represent various direction by  i , j, k . i representing east , j representing north and k representing vertically upward direction .

magnetic field is represented vectorially as follows

B = B₀ ( - i - j )

In the first case velocity of electron

v = v k

Force = q ( v x B )

= -e [ vk x B₀ ( - i - j ) ]

= evB₀ ( j -i )

Direction of force is north -west .

In the second case velocity of electron

v = vj

Force = -e [ vj x B₀ ( - i - j ) ]

= - evB₀ k

force is downward

In the third case, velocity of electron

v = v( -j +i )

Force = -e [ v( -j +i ) x B₀ ( - i - j ) ]

= 2 evB₀ k

Force is upward.

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Does specific heat change with mass?
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Ammonia, NH3, can be made by reacting nitrogen and hydrogen and the equation is N2 + 3H2 --&gt; 2NH3 How many moles of NH3 can b
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Make a proportion
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19H2 - x
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3 years ago
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