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3 years ago

14

When fluorine reacts, it will gain electron(s). O 3 O 1 ОО O2

1 answer:

ollegr [7]3 years ago

5 0

1 electron, fluorine requires one more electron to complete its outer shell.

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A wrench is used to tighten a spark plug. If the wrench handle is 0.20m and a force of 20N is applied, what is the torque applie

Zanzabum

Torque [Nm] = Force [N] x Force arm [m]

C=F*b=20*0.20=4 Nm

The correct answer is C

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3 years ago

What occurs when light changes direction after colliding with particles of matter

Slav-nsk [51]

Scattering occurs when light changes direction after colliding with particles of matter.

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3 years ago

Sam is walking at 2m/s down the hallway when he realized he will be late to class. He speeds up to 4m/s and makes it to English

Salsk061 [2.6K]

Answer:

.5 m/s²

Explanation:

a= (vf-vi)/t

a= (4-2)/4

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3 years ago

A jeweler working with a heated 47 g gold ring must lower the ring's temperature to make it safe to handle. If the ring is initi

Gelneren [198K]

Mass of gold m₁ = 47 g

Initial temperature of gold T₁ = 99 C

Specific heat of gold C₁ = 0.129 J/gC

final temperature T₂ = 38 C

Heat needed by the gold to cool down

Q =m₁ * C₁* ( T₁ - T₂)

Q = (47)(0.129)(99-38)

Q = 369.843 J

This heat will be given by the water

we need to find out mass of water m₂

and initial temperature of water is T₃ = 25 C

Specific heat of water C₂ = 4.184 J/gC

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6 0

3 years ago

Read 2 more answers

A thin taut string is fixed at both ends and stretched along the horizontal x-axis with its left end at x = 0. It is vibrating i

Fofino [41]

Answer:

(a) Wavelength is 0.436 m

(b) Length is 0.872 m

(c) 11.518 m/s

Solution:

As per the question:

The eqn of the displacement is given by:

$y(x, t) = (1.22 cm)sin[14.4 m^{- 1}x]cos[(166\ rad/s)t]$ (1)

n = 4

Now,

We know the standard eqn is given by:

$y = AsinKxcos\omega t$ (2)

Now, on comparing eqn (1) and (2):

A = 1.22 cm

K = $14.4 m^{- 1}$

$\omega = 166\ rad/s$

where

A = Amplitude

K = Propagation constant

$\omega$ = angular velocity

Now, to calculate the string's wavelength,

(a) $K = \frac{2\pi}{\lambda}$

where

K = propagation vector

$\lambda = \frac{2\pi}{K}$

$\lambda = \frac{2\pi}{14.4} = 0.436\ m$

(b) The length of the string is given by:

$l = \frac{n\lambda}{2}$

$l = \frac{4\times 0.436}{2} = 0.872\ m$

(c) Now, we first find the frequency of the wave:

$\omega = 2\pi f$

$f = \frac{\omega}{2\pi}$

$f = \frac{2\pi}{166} = 26.42\ Hz$

Now,

Speed of the wave is given by:

$v = f\lambda$

$v = 26.419\times 0.436 = 11.518\ m/s$

4 0

3 years ago