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4 years ago

A linear function f(x) is shown on the table. What is the value of f(4)

1 answer:

3 0

F(x)=y

y is considered to be the value of f(x)

Looking at a table, when x=4, the corresponding y value is the value of f(4)

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Can someone pls help me with these two

OverLord2011 [107]

That first one would be 14/ tan( 13)

The second would be 9 x cos(47)

8 0

3 years ago

Slove 44% of 82 finding a percentage of a number

Lelu [443]

36.08 in your calculator type in .44 multiplied by 82. Move the decimal point over two spots for your percent number. Example: 36% of 98 it would be .36 multiplied by 98. Hope this helps!

3 0

3 years ago

Read 2 more answers

Which expressions are equivalent to 71-x-3)? Select two options.

VikaD [51]

Answer:

68-x

Step-by-step explanation:

71-x-3=71-3-x=68-x

8 0

3 years ago

An economy package of cups has 720 green cups. If the green cups are 30% of the total package, how many cups are in the package?

TEA [102]

Answer:

Total number of cups in package are 2400.

Step-by-step explanation:

Given : An economy package of cups has 720 green cups.

And the green cups are 30% of the total package.

We have to find the number of total cups in the package.

Let the package contain x cups in total.

Given: green cups are 30% of the total package that is 30% of x,

Also , given package has 720 green cups.

Thus, 30% of x = 720

$30\%\times x= 720$

Solving for x, we have,

$\frac{30}{100}\times x=720\\\\\ x=720 \times \frac{100}{30}\\\\\ x=2400$

Thus, total number of cups in package are 2400.

6 0

3 years ago

Read 2 more answers

The average daily volume of a computer stock in 2011 was μ=35.1 million shares, according to a reliable source. A stock analyst

alexandr1967 [171]

Answer:

The 95% confidence interval is ( 27.126 , 34.674)

Step-by-step explanation:

Given

The t critical value at 0.05 level = 2.023 for the df = 39

Confidence interval = 95%

Mean

$\bar{x} - t * \frac{s}{\sqrt{n} } < \mu < \bar{x} + t * \frac{s}{\sqrt{n} }$

Substituting the given values we get -

$\30.9 - 2.023 * \frac{11.8}{\sqrt{40} } < \mu < \30.9 + 2.023 * \frac{11.8}{\sqrt{40} }\\27.126 < \mu < 34.674$

Hence, the 95% confidence interval is

( 27.126 , 34.674)

4 0

3 years ago