Answer:
a) v = 3 10⁶ m / s , b) a = 1.055 10¹² m / s² , c) r = 8.53 m
Explanation:
a) Let's use Newton's Second Law of Balance, so that electrons do not deviate
-
= 0
=
q E = q v B
v = E / B
Let's calculate
v = 6.0 10³ / 2.0 10⁻³
v = 3 10⁶ m / s
b) If the electric field is disconnected, the only force left is the magnetic one
= m a
q v B = m a
a = q / m v B
a = q / m (E / B) B
a = q / m E
a = 1.6 10⁻¹⁹ /9.1 10⁻³¹ 6.0 10³
a = 1.055 10¹² m / s²
c) Acceleration is centripetal
a = v² / r
r = v² / a
r = (3 10⁶)² /1.055 10¹²
r = 8.53 m
Answer:
Explanation:
The thermal efficiency of a Power cycle
where;
--- (1)
---- (2)
The coefficient of performance is:
let replace the value of in the above equation then;
The
On the other hand, the heat pump
By replacing equation (1) into the above equation; we have:
t
Answer:
A.
B. P ≈ 0
Explanation:
In order to calculate the magnetic field strength we have to use the magnetic field strength of a straight wire.
(eq. I)
B = magnetic field strength at distance d
I = current (A)
mi = represented by the greek letter μ, represents the permeability of the free space, which is: 4 × π 10^(-7) T m/A
d = distance from the wire
By replacing the values in eq I, we have the following:
(eq II)
The earth magnetic field in the surface variates from 25 to 65 microteslas. Thus:
P = Percentage from the wires/percentage of the earth
∵
∴
P ≈ 0
Answer:
v₃ = 9.62[m/s]
Explanation:
To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.
We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.
Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.
In this way, we can construct the following equation.
where:
m₁ = mass of the astronaut = 157 [kg]
m₂ = mass of the toolkit = 5 [kg]
v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]
v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]
v₃ = velocity at which the toolkit should be thrown [m/s]
Now replacing: