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Lapatulllka [165]
3 years ago
9

Name the type of component that has a greater resistance as the current through it increases​

Physics
1 answer:
Gnesinka [82]3 years ago
4 0

Answer:

filament bulb, filament lamp

Explanation:

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A block is sitting on a platform 20 m high. It weighs 50 kg. How much potential energy does it contain?
kifflom [539]

Answer:

9806.65 Joules

Explanation:

5 0
3 years ago
A machine produces a larger force than you exert to operate the machine. How does this input distance of the machine compare to
arlik [135]

Answer:

Because the output force is greater than the input force, the input distance must be greater than the output distance.

Explanation:

7 0
3 years ago
Enter an expression, in terms of defined quantities and g, for the force that the scale under left pillar shows
ella [17]

The expression, in terms of defined quantities and g is therefore Fu =((mg/2) +2 mp) g

<h3>What is a Scale?</h3>

This can be defined as a balance or any of various other instruments or devices for weighing.

The expression in terms of defined quantities and g, for the force that the scale under left pillar shows that Fu =((mg/2) +2 mp) g .

Read more about Force here brainly.com/question/4515354

5 0
1 year ago
What is a physical form in which a substance can exist?
Rama09 [41]
The three physical forms are:

Solid, liquid, or gas.

8 0
2 years ago
To avoid breakdown of the capacitors, the maximum potential difference to which any of them can be individually charged is 125 V
aleksley [76]

Answer:

The maximum energy stored in the combination is 0.0466Joules

Explanation:

The question is incomplete. Here is the complete question.

Three capacitors C1-11.7 μF, C2 21.0 μF, and C3 = 28.8 μF are connected in series. To avoid breakdown of the capacitors, the maximum potential difference to which any of them can be individually charged is 125 V. Determine the maximum energy stored in the series combination.

Energy stored in a capacitor is expressed as E = 1/2CtV² where

Ct is the total effective capacitance

V is the supply voltage

Since the capacitors are connected in series.

1/Ct = 1/C1+1/C2+1/C3

Given C1 = 11.7 μF, C2 = 21.0 μF, and C3 = 28.8 μF

1/Ct = 1/11.7 + 1/21.0 + 1/28.8

1/Ct = 0.0855+0.0476+0.0347

1/Ct = 0.1678

Ct = 1/0.1678

Ct = 5.96μF

Ct = 5.96×10^-6F

Since V = 125V

E = 1/2(5.96×10^-6)(125)²

E = 0.0466Joules

8 0
2 years ago
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