Name the type of component that has a greater resistance as the current through it increases

The author’s feeling about a subject or topic, which is evidenced in word choice, is called __________.

MatroZZZ [7]

The author’s feeling about a subject or topic, which is evidenced in word choice, is called tone. <span>They could be literal meanings which are meanings explicitly given to the readers or the person being told to. In this type of meaning, the person doesn’t need to think the words too much or ponder on the meaning because they could easily understand what the other person or the author implies. Meanwhile connotative meanings are meanings using different figures of speech or symbolism that the person still needs to think it over before knowing the actual meaning of the word, sentence or story.</span>

5 0

4 years ago

Read 2 more answers

100 POINTS!!! :D

charle [14.2K]

Explanation:

... in every interaction, there is a pair of forces acting on the two interacting objects. The size of the force on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.

4 0

3 years ago

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Sirius A is 8.6 light-years from Earth. What is this distance in kilometers? What is this distance in feet?

Jlenok [28]

Answer:

a. 8.136 × 10¹³ km b. 2.669 × 10¹⁹ feet

Explanation:

a. What is this distance in kilometers?

Since Sirius A is 8.6 light years away from Earth and one light year = distance travelled by light in a year = 3 × 10⁸ m/ s × 365 days/year × 24 hr/day × 3600 s/hr = 9.4608 × 10¹⁵ m = 9.4608 × 10¹² km.

Then 8.6 light years = 8.6 × 1 light year

= 8.6 × 9.4608 × 10¹² km

= 81.363 × 10¹² km

= 8.1363 × 10¹³ km

≅ 8.136 × 10¹³ km

b. What is this distance in feet?

Since 1 meter = 3.28 feet,

8.6 light years = 8.1363 × 10¹² km

= 8136.3 × 10¹⁵ m

= 8136.3 × 10¹⁵ × 1 m

= 8136.3 × 10¹⁵ × 3.28 feet

= 26687.1 × 10¹⁵ feet

= 2.66871 × 10¹⁹ feet

≅ 2.669 × 10¹⁹ feet

3 0

3 years ago

A car increases its speed from 20km/hr to 50km/hr in seconds. Its acceleration is _____.

mash [69]

Answer:

Option D

0.83 m/s2

Explanation:

Time is assumed as 10 seconds

First, convert the speeds from km/h to m/s

20 km/h\times \frac {1000 m}{3600 s}=5.555555556 m/s \approx 5.56 m/s

50 km/h\times \frac {1000 m}{3600 s}=13.88888889 m/s \approx 13.89 m/s

Acceleration, $a=\frac {v-u}{t}$ where u and v are the initial and final velocities respectively, t is the time taken to accelerate.

Substituting 13.89 m/s for v, 5.56 m/s for u and 10 s for t then

$a=\frac {13.89-5.56}{10}=0.8333333 m/s^{2}\approx 0.83 m/s^{2}$

7 0

3 years ago

Suppose your car accelerates from rest to 9 m/s in 2 s. Assume that the acceleration is constant in this time interval. A. What

Stolb23 [73]

Answer :

(a) The acceleration of the car is, $4.5m/s^2$

(b) The distance covered by the car is, 9 m

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 9 m/s

u = initial velocity = 0 m/s

t = time = 2 s

a = acceleration of the car = ?

Now put all the given values in the above equation 1, we get:

$9m/s=0m/s+a\times (2s)$

$a=4.5m/s^2$

The acceleration of the car is, $4.5m/s^2$

By the 2nd equation of motion,

$s=ut+\frac{1}{2}at^2$ ...........(2)

where,

s = distance covered by the car = ?

u = initial velocity = 0 m/s

t = time = 2 s

a = acceleration of the car = $4.5m/s^2$

Now put all the given values in the above equation 2, we get:

$s=(0m/s)\times (2s)+\frac{1}{2}\times (4.5m/s^2)\times (2s)^2$

By solving the term, we get:

$s=9m$

The distance covered by the car is, 9 m

3 0

3 years ago

Name the type of component that has a greater resistance as the current through it increases​

Name the type of component that has a greater resistance as the current through it increases