The maximum height that is reached by the ball is about 1.93 m
<h3>Further explanation</h3>
Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
<u>Given:</u>
mass of the ball = m₁ = 5.00 kg
mass of the stone = m₂ = 1.50 kg
initial velocity of the stone = u = 12.0 m/s
final velocity of the stone = v = -8.50 m/s
<u>Asked:</u>
maximum height of the ball = h = ?
<u>Solution:</u>
<em>Firstly, we will use </em><em>Conservation of Momentum Law </em><em>as follows:</em>
The speed of the ball is 6.15 m/s just after it hit by the stone.
<em>Next , we will use </em><em>Conservation of Energy </em><em>as follows:</em>
The maximum height that is reached by the ball is about 1.93 m
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Dynamics
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant