Answer:
The correct answer is:
(a) 84.240 kg
(b) 24.038 m
Explanation:
The given values are:
Force,
F = 81.0 N
Distance,
S = 13.0 m
Time,
t = 5.20 s
As we know,
The acceleration of mass will be:
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
⇒ 
(a)
The mass of the block will be:
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
(b)
The final velocity after a given time i.e.,
t = 5.00 s
⇒ 
On substituting the values, we get
⇒ 
⇒ 
In time, t = 5.00 s
The distance moved by the block will be:
⇒ 
On putting the values, we get
⇒ 
⇒ 
Given that,
mass m= 5.7 kg
Force of gravity = ?
Since,
Force of gravity acting on earth is equal to the weight and
W= mg
W= 5.7 * 9.81
W= 55.917
or
W= 56 N
Force of gravity acting on Earth by the package is 56 N.
Answer:
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Explanation:
Given initial velocity of ambulance
v0=18m/s , acceleration a=5m/s2
To find distance, x=?
First we need to calculate the time for which it acquires 30\,m/s. For that use equation
v=v0+at
30=18+5×t
⇒t=30−185=125seconds
Distance travelled by the ambulance
x=v0t+12at2
x=(18×125)+12×5×(125)2
x=43.2+2.5×5.76=43.2+14.4
x=57.6m
Therefore the ambulance has to travel 57.6 m to match the velocity of car.
Work = N × m = 50 x 40 = 2000 J
Answer:
Explanation:
Force on q due to Q
= k Qq / ( a² + d²)
x component
= k Qq / ( a² + d²) x d /√ ( a² + d²)
F = kQq d/ ( a² + d²)³/²
differentiating F with respect to d
dF / Dd = kQq [ d. -3/2 ( a² + d²)⁻⁵/² 2d + ( a² + d²)⁻³/²]=0 for maximum F
- 3d² / ( a² + d²) + 1 = 0
a² + d² = 3 d²
a² = 2d²
d = a / √2
