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Agata [3.3K]
3 years ago
6

Which of the following correctly describes the hierarchy that exists in the universe? A galaxy refers to all existing matter, en

ergy, and space that is held together by gravity. A galaxy is a collection of planets, their moons, and other objects in orbit around a central star. A solar system refers to all existing matter, energy, and space that is held together by gravity. A solar system is a collection of planets, their moons, and other objects in orbit around a central star.
Physics
2 answers:
Mkey [24]3 years ago
6 0
The correct hierarchy would be

-<span>A solar system is a collection of planets, their moons, and other objects in orbit around a central star.

</span><span>-A galaxy refers to all existing matter, energy, and space that is held together by gravity</span>
beks73 [17]3 years ago
3 0
<h3><u>Answer;</u></h3>
  • A galaxy refers to all existing matter, energy, and space that is held together by gravity
  • A solar system is a collection of planets, their moons, and other objects in orbit around a central star.
<h3><u>Explanation;</u></h3>
  • <em><u>The universe contains many galaxies and solar systems.</u></em>
  • <em><u>A galaxy </u></em>is a huge collection of gas, dust, and billions of stars and their solar systems.  A galaxy is held together by gravity. The galaxy that contains the Earth and its solar system is called the Milky Way.
  • <u>Solar System</u> consists of the stars, the Sun, and its orbiting planets, including the Earth, along with numerous moons, asteroids, comet material, rocks, and dust.

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When 2.50 g of a certain hydrocarbon was completely combusted in a "bomb (constant-volume) calorimeter" with a heat capacity (ex
erastovalidia [21]

Answer:

The thermal energy released per gram is 19.2 kJ/g.

(3)  is correct option.

Explanation:

Given that,

Weight of hydrocarbon = 2.50 g

Heat capacityc = 350 J/^{\circ}C

We need to calculate the thermal energy released

Using formula of thermal energy

Heat released =heat absorb by calorimeter+heat absorb by water

Q=c\Delta T+mc\Delta T

Put the value into the formula

Q=350\times5.52+2000\times4.184\times5.52

Q=48123.36\ J

Now, The thermal energy released per gram

Q'=\dfrac{Q}{m}

Put the value into the formula

Q'=\dfrac{48123.36}{2.50}

Q'=19.2\ kJ/g

Hence, The thermal energy released per gram is 19.2 kJ/g.

3 0
3 years ago
To practice Problem-Solving Strategy 15.1 Mechanical Waves. Waves on a string are described by the following general equation y(
DerKrebs [107]

Answer:

0.0549 m

Explanation:

Given that

equation y(x,t)=Acos(kx−ωt)

speed  v = 8.5 m/s

amplitude A = 5.5*10^−2 m

wavelength λ   = 0.5 m

transverse displacement = ?

v = angular frequency / wave number

and

wave number = 2π/ λ

wave number =  2 * 3.142 / 0.5

wave number = 12.568

angular frequency = v k

angular frequency = 8.5 * 12.568

angular frequency = 106.828 rad/sec ~= 107 rad/sec

so

equation y(x,t)=Acos(kx−ωt)

y(x,t)= 5.5*10^−2 cos(12.568 x−107t)

when x =0 and and t = 0

maximum y(x,t)= 5.5*10^−2 cos(12.568 (0) − 107 (0))

maximum y(x,t)= 5.5*10^−2  m

and when x =  x = 1.52 m and t = 0.150 s

y(x,t)= 5.5*10^−2 cos(12.568 (1.52) −107(0.150) )

y(x,t)= 5.5*10^−2 × (0.9986)

y(x,t) = 0.0549 m

so the transverse displacement is  0.0549 m

5 0
4 years ago
Why is the sky blue
ZanzabumX [31]
The answer is B. Gases and particles in earth’s atmosphere scatter sunlight in all directions
6 0
3 years ago
The magnetic field at the earth's surface can vary in response to solar activity. During one intense solar storm, the vertical c
Natalka [10]

Answer:

EMF = 1684.67 Volts

Explanation:

As we know that EMF is induced in a closed conducting loop if the flux linked with the loop is changing with time

So we can say

EMF = \frac{d\phi}{dt}

now we have

\phi = BA

here since magnetic field is constant so we have

EMF = A\frac{dB}{dt}

now we have

A = (190 \times 10^3)(190 \times 10^3)

A = 3.61 \times 10^{10} m^2

now we have

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6 0
3 years ago
The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb
Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 in^{2}

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = \frac{F}{A}

⇒ P = \frac{6.4}{0.4}

⇒ P = 16 \frac{lb}{in^{2} }

This is the pressure inside the cylinder.

Let force applied on the brake pad = F_{1}

Area of the brake pad (A_{1})= 1.7 in^{2}

Thus the pressure on the brake pad (P_{1}) =  \frac{F_{1} }{A_{1} }

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = P_{1}

⇒ 16 = \frac{F_{1} }{A_{1} }

⇒ F_{1} = 16 × A_{1}

Put the value of A_{1} we get

⇒ F_{1} = 16 × 1.7

⇒ F_{1} = 27.2 lb

This the total force applied during braking.

The force applied on one wheel = \frac{F_{1} }{4} = \frac{27.2}{4} = 6.8 lb

⇒ The force applied on one wheel during braking.

7 0
3 years ago
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