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mixer [17]
3 years ago
12

A 2.5-cm-diameter parallel-plate capacitor has a 2.2 mm spacing. The electric field strength inside the capacitor is 6.0×104 V/m

. You may want to review (Pages 699 - 702) . Part APart complete What is the potential difference across the capacitor? Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
vladimir2022 [97]3 years ago
3 0

Explanation:

The given data is as follows.

     Separation between two plates, d = 2.2 mm = 2.2 \times 10^{-3} m

     Electric field strength inside the capacitor, E = 6.0 \times 10^{4} V/m

Therefore, we will calculate the potential difference across the capacitor as follows.

              V = Ed

                  = 6.0 \times 10^{4} V/m \times 2.2 \times 10^{-3} m

                  = 1.32 V

Thus, we can conclude that the potential difference across the given capacitor is 1.32 V.

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Below are three graphs. The shape of graph 3 shows that the current flowing through this component is __________ proportional to
dalvyx [7]

The relationship between variables might be either directly porportional to each other or inversely proportional to each other. <em>For instance, the current flowing is _</em><em><u>directly</u></em><em>_ </em><em>proportional to the potential difference across</em> it.

---------------------

Since I do not have the graph, I will propose two potential options and I will describe each of them.

I suggest you to choose the one that matches the shape of graph 3.

<h3>Graphs</h3>
  • Probably your graph is composed of the X and Y axes, perpendicularly placed, in a way in which four quadrants are formed.

  • You might see that one of the axes represents the current (I), and the other one represents the potential difference (V).

  • And a straight line that represents the relationship between the current and the potential difference.

  • The direction of the straight line reflects the relationship between variables.

  • The change on each variable is proportional to the change on the other variable. Now we have to analyze how that change occurs.
<h3 /><h3>Option 1 </h3>

<em>The current flowing through this component is __</em><u><em>DIRECTLY</em></u><em>__ proportional to the potential difference across it</em>.

If this is the case of your graph, you should see the straight line crossing from the left inferior quadrant to the right superior one.

The direction of the line suggests that one of the variables increases as the other one increases too. <em>The current increases as the potential increases. </em>

<h3> </h3>

<em>This is the case of the </em><em>Ohm's law.</em><em> </em>

<h3 /><h3 /><h3>Option 2 </h3>

<em>The current flowing through this component is __</em><u><em>INVERSELY</em></u><u><em>_</em></u><em>_ proportional to the potential difference across it.</em>

If this is the case of your graph, you should see the straight line crossing the right quadrant from the superior left corner to the inferior right one.

The direction of the line suggests that the variable represented in the Y ax decreases as the other one increases.

For instance, The current decreases as the potential increases. Or the potential decreases as the current increases.

In the attached files you will find graphs of both options.

-------------------------

You can learn more about the Ohm's law at  

brainly.com/question/17286882?referrer=searchResults

You can learn more about the relationship between variables at

brainly.com/question/16937826?referrer=searchResults

brainly.com/question/21627823?referrer=searchResults

6 0
2 years ago
The rings of Saturn occupy the region inside Saturn's Roche limit.
Oliga [24]
I suppose this is a true or false question and that sentence is true.
7 0
3 years ago
The energy band gap of GaAs is 1.4eV. calculate the optimum wavelength of light for photovoltaic generation in a GaAs solar cell
Viktor [21]

Answer:

λ = 8.88 x 10⁻⁷ m = 888 nm

Explanation:

The energy band gap is given as:

Energy Gap = E = 1.4 eV

Converting this to Joules (J)

E = (1.4 eV)(1.6 x 10⁻¹⁹ J/1 eV)

E = 2.24 x 10⁻¹⁹ J

The energy required for photovoltaic generation is given as:

E = hc/λ

where,

h = Plank's Constant = 6.63 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light = ?

Therefore,

2.24 x 10⁻¹⁹ J = (6.63 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/λ

λ = (6.63 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(2.24 x 10⁻¹⁹ J)

<u>λ = 8.88 x 10⁻⁷ m = 888 nm</u>

7 0
3 years ago
A 49-year-old female was referred for mammography, but she is very apprehensive after reading about the risk of ionizing radiati
SOVA2 [1]

Answer:

Mammography is the process in which low energy radiations are used to diagnose and screening. The purpose of this process is the early detection of the breast cancer. These low energy radiations may have some risks like damaging and burning of cells.  

In the current scenario, woman is apprehensive because she has read about the risks of using ionizing radiations. The radiographer should tell her the benefits of the mammography will outweigh its potential consequences. Screening, for instance, will let her know if she is suffering from breast cancer. Cancer is very dangerous disease as compare to very small burning.

In this way radiographer should handle the situation.

4 0
3 years ago
g In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constr
Lorico [155]

To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.

In other words the acceleration can be described as

a = \frac{GM}{r^2}

Where

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius of Earth

This equation can be differentiated with respect to the radius of change, that is

\frac{da}{dr} = -2\frac{GM}{r^3}

da = -2\frac{GM}{r^3}dr

At the same time since Newton's second law we know that:

F_w = ma

Where,

m = mass

a =Acceleration

From the previous value given for acceleration we have to

F_W = m (\frac{GM}{r^2} ) = 600N

Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:

dF_W = mda

dF_W = m(-2\frac{GM}{r^3}dr)

dF_W = -2(m\frac{GM}{r^2})(\frac{dr}{r})

dF_W = -2F_W(\frac{dr}{r})

But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:

dF_W = -2(600)(\frac{1.6*10^3}{6.37*10^6})

dF_W = -0.3N

Therefore there is a weight loss of 0.3N every kilometer.

4 0
3 years ago
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