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2 years ago

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A 2000 g of C 14 is left to decay radioactively the half-life of Corbin 14 is approximately 5700 years what fraction of that sam

ple remain after 17,100 years

2 answers:

ahrayia [7]2 years ago

8 0

Answer:

1/8

Explanation:

17,100 years is 3 times the half-life of 5,700 years. After each half-life, half remains, so the amount remaining after 3 half-lives is ...

(1/2)(1/2)(1/2) = 1/8

1/8 of the sample remains after 17,100 years.

agasfer [191]2 years ago

6 0

Answer:

1/8

Explanation:

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Answer:

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Explanation:

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Now substituting values accordingly

$k = \frac{4.9}{0.6}$

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$E_T = initial \ elastic\ potential \ energy + kinetic \ energy$

$E_T = \frac{1}{2} k D_{max}^2 = \frac{1}{2} k D^2 + \frac{1}{2} mv^2$

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$4.085 * D_{max}^2 = 3.69$

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$D_{max} = 0.950m$

So to obtain total length we would add the unstretched length

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Answer

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