Answer:
Epx= - 21.4N/C
Epy= 19.84N/C
Explanation:
Electric field theory
The electric field at a point P due to a point charge is calculated as follows:
E= k*q/r²
E= Electric field in N/C
q = charge in Newtons (N)
k= electric constant in N*m²/C²
r= distance from load q to point P in meters (m)
Equivalences
1nC= 10⁻⁹C
known data
q₁=-2.9nC=-2.9 *10⁻⁹C
q₂=5nC=5 *10⁻⁹C
r₁=0.840m



Calculation of the electric field at point P due to q1
Ep₁x=0

Calculation of the electric field at point P due to q2


Calculation of the electric field at point P(0,0) due to q1 and q2
Epx= Ep₁x+ Ep₂x==0 - 21.4N/C =- 21.4N/C
Epy= Ep₁y+ Ep₂y=36.95 N/C-17.11N =19.84N/C
A car is built from various subsystems. If these subsystems are not working properly it is dangerous because it can cause a serious traffic accident.
<h3>What subsystems do cars have?</h3>
When you're testing the build of a car, you have to check its many subsystems:
- the battery
- the engine
- the cabin
- the thermal-management system
- the gearbox
- the chassis
- the suspension
<h3>Why is a car with damaged subsystems dangerous?</h3>
The subsystems of a car are very important components that allow the proper functioning of the car. These subsystems work synchronously making the car work properly.
However, if one of these subsystems is not working properly it could cause a malfunction that could lead to a traffic accident.
Learn more about cars in: brainly.com/question/11733094
Correct answer choice is:
D. A continuous transmission of energy from one location to the next.
Explanation:
Waves include the carrier of energy without the carrier of matter. In outcome, a wave can be characterized as a change that progresses into a medium, carrying energy from one spot (its source) to different spot without carrying matter.
Answer:
Uncorrected values for
For circuit P
R = 2.4 ohm
For circuit Q
R = 2.4 ohm
Corrected values
for circuit P
R = 12 OHM
For circuit Q
R = 2.3 ohm
Explanation:
Given data:
Ammeter resistance 0.10 ohms
Resister resistance 3.0 ohms
Voltmeter read 6 volts
ammeter reads 2.5 amp
UNCORRECTED VALUES FOR
1) circuit P
we know that IR =V

2) circuit Q
R = 2.4 ohm as no potential drop across ammeter
CORRECTED VALUES FOR
1) circuit p
IR = V

R= 12 ohm
2) circuit Q


R = 2.3 ohm
Answer:
I think it is D but don't count on it