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Cerrena [4.2K]
3 years ago
6

A constant braking force of 10 newtons applied for 5 seconds is used to stop a 2.5-kilogram cart traveling at 20 meters per seco

nd. the magnitude of the impulse applied to stop the cart is
Physics
2 answers:
ss7ja [257]3 years ago
6 0
Mathematically it can be expressed as: I = FpΔt. Where F p is the average magnitude of the acting force and Δt = t 2 - t 1, the time lapse in the force acts.
 The magnitude of the impulse applied to stop the cart is
 I = FpΔt = (10N) * (5s) = 50 N.s
inn [45]3 years ago
4 0

Answer:The magnitude of the impulse applied to stop the cart is 50 N sec.

Explanation:

Force applied on the cart = 10 N

Interval of time till force applied ,Time= 5 second

Impulse=Force\times Time=10 N\times 5 seconds= 50 N seconds

The magnitude of the impulse applied to stop the cart is 50 N sec.

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