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xz_007 [3.2K]
3 years ago
13

44. A mediados de la década de 1960, la McGill University lanzó sensores metereológicos de gran altitud al dispararlos desde un

cañón hecho de dos cañones de la Armada de la Segunda Guerra Mundial, atornillados uno tras otro para tener una longitud total de 18 m. Se propuso que este arreglo se usara para lanzar un satélite. La rapidez orbital de un satélite es de unos 29 000 km/h. ¿Cuál tendría que ser la aceleración me- dia a lo largo de los 18 m del cañón, para tener una velocidad de 29 000 km/h a la salida de la boca del cañón para este sa- télite? ​
Physics
1 answer:
Afina-wow [57]3 years ago
4 0

La cinemática permite encontrar la respuesta para la aceleracion del cuerpo en el cañón es:

            a = 1,8 10⁶ m/s²  

 

La cinemática estudia el movimiento de los cuerpos, buscando relaciones entre la posicion, la velocidad y la aceleración.

       v² = v₀² + 2 a x

Donde v y v₀ son la velocidad actual e inicial, respectivamente, a es la aceleracion y x la distancia recorrida.

Indica que la longitud de cañon es x= 18 m la velocidad de  salida es  

            v= 29000 km/h ( \frac{1000m}{1 km} ) ( \frac{1h}{3600s} s) = 8,055,56 m/s.

La velocidad inicial del proyectil es cero.

            a = \frac{v^2}{2x}  

            a = \frac{ 8055.56^2}{2 \ 18}  

            a = 1,8 10⁶ m/s²  

En conclusión usando la cinemática podemos encontrarla respuesta para la aceleracion del cuerpo en el cañón es:

            a = 1,8 10⁶ m/s²  

Aprender mas aquí:  brainly.com/question/19793086

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Answer:

0.358Kg

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Using conservation of momentum between the bullet and the block

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12.56 = 0.5 × 9.2872/ M + 0.0115

12.56 = 4.6436/ M + 0.0115

12.56 ( M + 0.0115 ) = 4.6436

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