Ask question

Ask question

All categories

2 years ago

13

44. A mediados de la década de 1960, la McGill University lanzó sensores metereológicos de gran altitud al dispararlos desde un

cañón hecho de dos cañones de la Armada de la Segunda Guerra Mundial, atornillados uno tras otro para tener una longitud total de 18 m. Se propuso que este arreglo se usara para lanzar un satélite. La rapidez orbital de un satélite es de unos 29 000 km/h. ¿Cuál tendría que ser la aceleración me- dia a lo largo de los 18 m del cañón, para tener una velocidad de 29 000 km/h a la salida de la boca del cañón para este sa- télite?

1 answer:

Afina-wow [57]2 years ago

4 0

La cinemática permite encontrar la respuesta para la aceleracion del cuerpo en el cañón es:

a = 1,8 10⁶ m/s²

La cinemática estudia el movimiento de los cuerpos, buscando relaciones entre la posicion, la velocidad y la aceleración.

v² = v₀² + 2 a x

Donde v y v₀ son la velocidad actual e inicial, respectivamente, a es la aceleracion y x la distancia recorrida.

Indica que la longitud de cañon es x= 18 m la velocidad de salida es

v= 29000 km/h ( $\frac{1000m}{1 km}$ ) ( $\frac{1h}{3600s}$ s) = 8,055,56 m/s.

La velocidad inicial del proyectil es cero.

a = $\frac{v^2}{2x}$

a = $\frac{ 8055.56^2}{2 \ 18}$

a = 1,8 10⁶ m/s²

En conclusión usando la cinemática podemos encontrarla respuesta para la aceleracion del cuerpo en el cañón es:

a = 1,8 10⁶ m/s²

Aprender mas aquí: brainly.com/question/19793086

You might be interested in

A typical human consumes 2500 Kcal of energy during a day. This is the equivalent to 10,450,000 J! Say you decided to run stairs

defon

Answer:

2940.1 joules would you burn in climbing stairs all day.

Explanation:

Work = W = F $\times$ d

going up stairs would be against force of gravity

W = mgh

where h is the height

the question is not complete because we need speed or distance

h = v $\times$ t

so assuming 1 step per second

h = 86,400 steps $\times$ 7inchs/step $\times$ 0.0254 m/inch

h = 15362 m

so from this

W = 800 N $\times$ 15362

= 12289600 J

that means YOU need 12289600 J to walk 1 step per second all day

divide that by 4180 J /Kcal

Kcal = $\frac{W}{(J/Kcal)}$

= $\frac{12289600}{4180}$

= 2940.1 Kcal

if you ran faster you would use more energy 2 steps per second would mean 5880 Kcal.

8 0

3 years ago

An industrial firm has two electrical loads connected in parallel across the power source. Power is supplied to the firm at 4000

Andrei [34K]

Answer:

I = 27.65A < 40.59°

PowerFactor = 0.76

Explanation:

Current on the heating load is:

I1 = 30KW / 4KV = 7.5A < 0°

Current on the inductive load:

I2 = (150KVA*0.6) /4KV = 22.5A with an angle of acos(0.6)=53.1°

The sum of both currents is:

It = I1 + I2 = 7.5<0° + 22.5<53.1° = 27.65<40.59°

Now, the power factor will be:

pf = cos (40.59°) = 0.76

7 0

3 years ago

A retail gasoline pump is able to fill a 14.0 gallon automobile tank in 1.50 minutes. What is the mass flow rate deliverd by the

Ludmilka [50]

We have volume of gasoline = 14.0 gallon

Time taken to fill automobile tank = 1.50 minutes

So volume rate = 14.0 gallon/1.50 minutes = 9.33 gallon/ minute

We have density of gasoline = 0.77 kg/L = 6.073 lb/US gal

Mass rate = Density * Volume rate

= 9.33 gallon/ minute*6.073 lb/US gal = 56.68 lb/min

So mass flow rate delivered by the gasoline pump in lbm/min = 56.68

6 0

3 years ago

Read 2 more answers

A ball is falling from the sky down to the left. What two forces are being used?

suter [353]

Answer:

push and pull

Explanation:

i beleve good luck❤️❤️

4 0

2 years ago

Read 2 more answers

A ray of light passes from air into a block of clear plastic. How does the angle of incidence in the air compare to the angle of

andre [41]

Answer:

The angle of incidence is greater than the angle of refraction

Explanation:

Refraction occurs when a light wave passes through the boundary between two mediums.

When a ray of light is refracted, it changes speed and direction, according to Snell's Law:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where :

$n_1$ is the index of refraction of the 1st medium

$n_2$ is the index of refraction of the 2nd medium

$\theta_1$ is the angle of incidence (the angle between the incident ray and the normal to the boundary)

$\theta_2$ is the angle of refraction (the angle between the refracted ray and the normal to the boundary)

In this problem, we have a ray of light passing from air into clear plastic. We have:

$n_1=1.00$ (index of refraction of air)

$n_2=1.50$ approx. (index of refraction in clear plastic)

Snell's Law can be rewritten as

$sin \theta_2 =\frac{n_1}{n_2}sin \theta_1$

And since $n_2>n_1$ , we have

$\frac{n_1}{n_2}$

And so

$\theta_2$

Which means that

The angle of incidence is greater than the angle of refraction

6 0

3 years ago