The intersection of two planes is a line. That's not necessarily the definition of a line, but that's probably what they're looking for.
Answer: line
X-7=13
move -7 to the right side of the equation, change the sign from negative to positive when you move it
x-7+7=13+7
x=13+7
x=20
The equation of a line in the slope intercept form is expressed as
y = mx + c
Where
m represents slope
c represents y intercept
The equation of the given line is expressed as
3x - 6y = 30
Rearranging it so that it will look like the slope intercept form, it becomes
6y = 3x - 30
Dividing both sides by 6, it becomes
6y/6 = 3x/6 - 30/6
y = x/2 - 5
Looking at the equation, slope, m = 1/2
If two lines are parallel, it means that they have equal slope. This means that the slope of the line parallel to the given line is 1/2
To determine the y intercept, c of the line passing through the point (4, - 9), we would substitute
x = 4, y = - 9 and m = 1/2 into the slope intercept equation. It becomes
- 9 = 1/2 * 4 + c
- 9 = 2 + c
c = - 9 - 2
c = - 11
By substtuting m = 1/2 and c = - 11 into the slope intercept equation, the equation of the line would be
y = x/2 - 11
Answer:
The solutions are a₁ = -4/19 i, a₂ = 4/19 i and a₃ = -1/4
Step-by-step explanation:
Given the equation 76a³+19a²+16a=-4, for us to solve the equation, we need to find all the factors of the polynomial function. Since the highest degree of the polynomial is 3, the polynomial will have 3 roots.
The equation can also be written as (76a³+19a²)+(16a+4) = 0
On factorizing out the common terms from each parenthesis, we will have;
19a²(4a+1)+4(4a+1) = 0
(19a²+4)(4a+1) = 0
19a²+4 = 0 and 4a+1 = 0
From the first equation;
19a²+4 = 0
19a² = -4
a² = -4/19
a = ±√-4/19
a₁ = -4/19 i, a₂ = 4/19 i (√-1 = i)
From the second equation 4a+1 = 0
4a = -1
a₃ = -1/4
Hmm I use to know this wait a second I’ll answer it
