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Korvikt [17]
3 years ago
11

What is the greatest 0.45 0.097 0.375 0.209

Mathematics
2 answers:
Luda [366]3 years ago
6 0
0.45 is the greatest
Nady [450]3 years ago
3 0

Answer:

Largest number is : 0.45

Step-by-step explanation:

0.45, 0.097, 0.375, 0.209

Here all numbers have first digit is 0.

So, look at the first decimal place from all decimal numbers.

4 from .45, 0 from .097, 3 from .375 and 2 from .209

Largest digit is 4

So, largest digit is 0.45

So, final answer is 0.45

I hope it will help you.

If you have any doubt, please leave a comment. I'll help you.

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rosijanka [135]

Using the limit definition of the derivative, you have

\displaystyle f'(-5) = \lim_{x\to-5} \frac{f(x) - f(-5)}{x - (-5)} = \lim_{x\to-5} \frac{(2x^2+4x+7) - 37}{x + 5}

Simplify the numerator:

(2<em>x</em> ² + 4<em>x</em> + 7) - 37 = 2<em>x</em> ² + 4<em>x</em> - 30

… = 2 (<em>x</em> ² + 2<em>x</em> - 15)

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Then

\displaystyle f'(-5) = \lim_{x\to-5}\frac{2(x+5)(x-3)}{x+5} = \lim_{x\to-5} 2(x-3) = \boxed{-16}

• • •

For your second question in the comments, if <em>f(x)</em> = -2<em>x</em> ² + 3<em>x</em> - 7, then by the definition of the derivative, you have

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{(-2(x+h)^2+3(x+h)-7) - (-2x^2 + 3x - 7)}h

Simplify the numerator:

(-2 (<em>x</em> + <em>h</em>)² + 3 (<em>x</em> + <em>h</em>) - 7) - (-2<em>x</em> ² + 3<em>x</em> - 7)

… = (-2<em>x</em> ² - 4<em>xh</em> - 2<em>h</em> ² + 3<em>x</em> + 3<em>h</em> - 7) - (-2<em>x</em> ² + 3<em>x</em> - 7)

… = -4<em>xh</em> - 2<em>h</em> ² + 3<em>h</em>

Now compute the limit:

\displaystyle f'(x) = \lim_{h\to0}\frac{-4xh-2h^2+3h}h = \lim_{h\to0}(-4x-2h+3) = \boxed{-4x+3}

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Rus_ich [418]
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Step-by-step explanation:

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••••••••••••••••••••••••••••••••••••

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