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Butoxors [25]
3 years ago
15

3. A 64 lb weight stretches a spring 4 ft in equilibrium. The weight is initially displaced 6 inches above equilibrium and given

a downward velocity of 6 ft/sec. Find its displacement for t > 0 if the medium resists the motion with a force equal to 3 times the speed in ft/sec (that is, the damping constant c = 3). Note that there is no external force in this case.

Physics
1 answer:
Damm [24]3 years ago
6 0

Answer:

Explanation:

the solution is given in the attached pictures

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1. Dos puntos A y B están separados en línea recta 1475 m. Por el punto A pasa hacia el punto B un móvil con una velocidad de 15
ikadub [295]

Answer:

a) 35 sequndos   b) M1 = 600m   M2 = 875m

Explanation:

a)

Antes de que el otro móvil comience a moverse, el primer móvil ha viajado 5 segundos a una velocidad de 15 m / s.

5 segundos x 15 m / s = 75 metros.

Podemos establecer una ecuación con la información que conocemos. Juntos, en total, los dos recorren 1475 metros.

Voy a representar el tiempo como t. Un móvil ya ha recorrido 75 metros y hará otros 15 t. El otro aún no se ha movido y viajará 25t. Esos tres números se sumarán a 1475.

75 + 15t + 25t = 1475.

Resta 75 de ambos lados y suma términos similares de t: 40t = 1400

t = 35 segundos.

b)

Ahora tome la distancia recorrida por cada vehículo por separado y conecte 35 segundos para t.

Primer móvil: 75 + 15t = 75 + 15 (35) = 600m

Segundo móvil: 25t = 25 (35) = 875m

Usé un traductor para entender la pregunta y luego traduje lo que escribí. Lo siento si mi explicación no es clara.

6 0
4 years ago
Why is the surface salinity of the ocean higher in the subtropics than in equatorial regions?
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what chemical change occurs when a movie reactive substance replaces a less reactive substance in a compound
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6 0
3 years ago
Which is easier for a beginner? (This is for archery)<br><br> O long bow<br><br> O recurve bow
AlexFokin [52]

Answer:

The recurve bows

Explanation:Vote brainliest plz

6 0
3 years ago
Read 2 more answers
You are driving your car, and the traffic light ahead turns red. you apply the brakes for 2.26 s, and the velocity of the car de
Lorico [155]

Let the initial velocity of the car be u.

Final velocity of the car (v) = 5.43 m/s

deceleration (a) = - 2.78 m/s^2

Time taken (t) = 2.26 s

Using the first equation of motion:

v = u + at

u = v - at

u = 5.43 - (-2.78 \times 2.26)

u = 5.43 + 6.28

u = 11.71 m/s

Let the car's displacement be x.

Using second equation of motion:

x = ut + \frac{1}{2}at^2

x = 11.71 \times 2.26 - \frac{1}{2} \times 2.78 \times 2.26^2

x = 26.4646 - 7.0995

x = 19.3651 meters

Hence, the displacement of the car is 19.36 meters

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4 years ago
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