3. A 64 lb weight stretches a spring 4 ft in equilibrium. The weight is initially displaced 6 inches above equilibrium and given
a downward velocity of 6 ft/sec. Find its displacement for t > 0 if the medium resists the motion with a force equal to 3 times the speed in ft/sec (that is, the damping constant c = 3). Note that there is no external force in this case.
1 answer:
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Answer:
and
Explanation:
According to Coulomb's law, the magnitude of force between two point object having change and
and by a dicstanced is
Where, is the permitivity of free space and
in SI unit.
Before dcollision:
Charges on both the sphere are and
, d=20cm=0.2m, and
N
So, from equation (i)
After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.
Charges on both the sphere are mean of total charge, i.e
d=20cm=0.2m, and N
So, from equation (i)
As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.
The equation (ii) become:
From equation (iii)
So, the magnitude of initial charges on both the sphere are Coulombs
and
Colombs or
.
Considerion the nature of charges too,
and