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Zinaida [17]
3 years ago
6

A Blu-ray disc is approximately 8 centimeters in diameter. The drive motor of the Blu-ray player is able to rotate up to 10,000

revolutions per minute, depending on what track is being read. (a) Find the maximum angular speed (in radians per second) of a Blu-ray disc as it rotates.

Physics
2 answers:
Ray Of Light [21]3 years ago
8 0

Answer:

The question is incomplete. Here is the complete question:

A Blu-ray disc is approximately 8 centimeters in diameter. The drive motor of the Blu-ray player is able to rotate up to 10,000 revolutions per minute, depending on what track is being read. (a) Find the maximum angular speed (in radians per second) of a Blu-ray disc as it rotates. (b) Find the maximum linear speed (in meters per second) of a point on the outermost track as the disc rotates.

Answer:

(a) 1047.2 rad/sec

(b) 41.9 m/s

Explanation: Please see the attachments below

Elodia [21]3 years ago
7 0

Answer:

1047.193radians/s.

Explanation:

10,000revs/min = 166.6666revs/s

1 revolution = 360 degrees = 2\pi radians

so 10,000 revolutions= 2*\pi *166.666 = 1047.193radians.

so maximum angular speed is.

1047.193radians/second.

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a gym consists of a rectangular region with a semi-circle on each end. if the perimeter of the room is to be a 200 m running tra
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The dimensions of the rectangle are:

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<h3>What is a perimeter in math?</h3>

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

<h3>How do we find a perimeter of a rectangle?</h3>

The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.

<h3>Given:</h3>

As per the question:

Perimeter of the room is given as P = 200 m

The region is rectangular having a semicircle at each end.

Now,

Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.

Then, Area of the given rectangle, A = lb

Perimeter of the room, P is =\pi r+l+\pi r+l=2\pi r+2l=\pi b+2l

Therefore,  \pi b+2l=200

b=(200-2l)/\pi

Now,

Area, A = l(200-2l)/\pi=(200l-2l^{2} )/\pi

Now, differentiate A w.r.t l:

Again differentiating w.r.t 'l', we get:

d^{2} A/dl^{2} =-4l/\pi< 0

Thus we get maximum are when dA/dl=0

Therefore,

(200-4l)/\pi=0

l = 50 m

Now, from

\pi b+2l=200

\pi b=200-2*50

b=100/\pi

r=b/2=50/\pi

To know more about area of a recatangle, visit the link

brainly.com/question/20693059

#SPJ4

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