I need help please for geometry

Mathematics

1 answer:

mart [117]3 years ago

6 0

Answer:

EF ≈ 1.98

Step-by-step explanation:

Using the sine ratio in the right triangle

sin26° = $\frac{opposite}{hypotenuse}$ = $\frac{EF}{FD}$ = $\frac{EF}{4.5 }$ ( multiply both sides by 4.5 )

4.5 × sin26° = EF

4.5 × 0.44 = EF , that is

EF ≈ 1.98 ( to 2 dec. places )

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9(5x + 1) ÷ 3y

Ivan

Some definitions:

Sum - the result of adding values together

Term - a single number or variable (includes variables multiplied by numbers)

Factor - a number or variable that divides another number or expression evenly

Quotient - the result of dividing values by one another

Coefficient - a numerical or constant value often in front of a variable

In your equation:

Sum - (5x + 1)

5x and 1 are being added together, although we do not know the sum exactly, we know that the sum is equal to the value of 5 times x plus 1.

Term - (5x, 1, 3y)

All terms given above are applicable.

Factor - (9)

9 has been taken out of the expression that it is now being multiplied, which shows that it was factored out of that expression

Quotient - (9(5x + 1) / 3y)

The value of 9(5x + 1) is being divided by 3y. Though we do not know the quotient exactly, we know that the quotient is equal to the values given.

Coefficient - (5, 3)

Both 5 and 3 are numbers in front of variables.

Hope this helps!! :)

3 0

2 years ago

1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t

Sophie [7]

$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70