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adoni [48]
2 years ago
9

What is the coefficient of m3 in the expression 4m + 7 + 3m3? 4 7 3 3 m 3

Mathematics
1 answer:
AveGali [126]2 years ago
6 0

Answer:

3 is the coefficient of m3

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The Boardman family walked two over five of a mile in two over seven of an hour. What is their unit rate in miles per hour?
vitfil [10]

Answer:

two-fifths over two-sevenths equals one and two-fifths miles per hour .

6 0
2 years ago
Read 2 more answers
Determine an equivalent algebraic monomial expression using the laws of exponents. Show your work.
Serga [27]

The equivalent algebraic monomial expression of the expression given as (-8a^5b)(3ab^4) is -24a^6b^5

<h3>How to determine an equivalent algebraic monomial expression?</h3>

The expression is given as:

(-8a^5b)(3ab^4)

Multiply -8 and 3

So, we have:

(-8a^5b)(3ab^4) = (-24a^5b)(ab^4)

Multiply a^5 and a (a^5 * a = a^6)

So, we have:

(-8a^5b)(3ab^4) = (-24a^6b)(b^4)

Multiply b and b^4

So, we have:

(-8a^5b)(3ab^4) = -24a^6b^5

Hence, the equivalent algebraic monomial expression of the expression given as (-8a^5b)(3ab^4) is -24a^6b^5

Read more about expressions at:

brainly.com/question/723406

#SPJ1

4 0
1 year ago
Parallelogram abcd has verticals at A(0,0), B(3,6), C(5,5) and D(2,-1) which conclusion can be made ?
sertanlavr [38]

Answer:

A.

Step-by-step explanation:

when you plot the vertices;

Side AB is perpendicular to side BC

Side AB is parallel to side DC

Side AC is perpendicular to AB

Side AC is perpendicular to DC

Side AC is parallel to side BC

The conclusion made is that ABCD is a rectangle

8 0
3 years ago
Write an expression to match the words three times the sum of 8and 4
vfiekz [6]
3x8+4 because 3 times so that is 3 x the sum of 8 and 4 so 8+4 together it would be 3x8+4
5 0
3 years ago
Read 2 more answers
In circle K shown below, points B, C, D, and E lie on the circle with secants HBD and HCE drawn. Prove:
Alexxx [7]

Answer:

By exterior angle theorem, we have;

∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC

∴ ∠H + ∠HEB = ∠H + ∠HDC

By addition property of equality, we have

∠HEB = ∠HDC

∠H = ∠H by reflexive property

∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate

∴ HE/HD = EB/DC, by the definition of similarity

Therefore, by cross multiplication, we have;

HE × DC = EB × HD

Therefore, by commutative property of multiplication, we have;

HE × DC = HD × EB

Step-by-step explanation:

3 0
3 years ago
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