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AysviL [449]
3 years ago
12

Your grandmother gave you $6 with which to buy a present. This covered 3/8 of the cost. How much did the present cost?

Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0
The present cost 16$.
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Hello, I'm trying to solve 6x + y = 4, x - 4y = 19. I have found the y but I cant seem to find the x. Plz help and we cant use d
gizmo_the_mogwai [7]

Answer:

x=\frac{7}{5}

y=-\frac{22}{5}

Step-by-step explanation:

Given:

The given expressions are.

6x+y=4

x-4y=19

We need to find x and y values.

Solution:

Equation 1⇒ 6x+y=4

Equation 2⇒ x-4y=19

First solve the equation 1 for y.

6x+y=4

y = 4-6x --------(3)

Substitute y = 4-6x in equation 2.

x-4(4-6x)=19

Simplify.

x-(4\times 4 - 4\times 6x)=19

x-(16-24x)=19

x-16+24x=19

Add 16 both side of the equation.

25x-16+16=19+16

25x=35

x=\frac{35}{25}

Divide Numerator and denominator by 5.

x=\frac{7}{5}

Substitute x value in equation 3 and simplify.

y=4-6(\frac{7}{5})

y=4-\frac{6\times 7}{5}

y=4-\frac{42}{5}

y=\frac{5\times 4-42}{5}

y=\frac{20-42}{5}

y=-\frac{22}{5}.

Therefore, the value of x=\frac{7}{5} and y=-\frac{22}{5}.

6 0
3 years ago
Solve for 2.<br> - 6x + 2x = -4<br> 6<br> 4<br> 1<br> -6
NNADVOKAT [17]
The answer is c) x=1
6 0
2 years ago
Read 2 more answers
|3x-4| +2=1<br> Please help!
fomenos

1.6 !!!!!!!!!! x=1.6 !!!!!

3 0
3 years ago
Can you think of any 2x2 matrices d for which cd = dc for all 2x2 matrices c? give 2 different examples of such matricesd.
Ksju [112]
For any arbitrary 2x2 matrices \mathbf C and \mathbf D, only one choice of \mathbf D exists to satisfy \mathbf{CD}=\mathbf{DC}, which is the identity matrix.

There is no other matrix that would work unless we place some more restrictions on \mathbf C. One such restriction would be to ensure that \mathbf C is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking \mathbf D=\mathbf C^{-1} we'd get equality.
6 0
3 years ago
Help please :]!!<br> please be right,
pickupchik [31]
I think it’s c I had this question lol
8 0
2 years ago
Read 2 more answers
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