<span>342.15g/mol I'm not for sure though </span>
<span>Sand dunes are formed from wind
movement. There needs to be a large amount of loose sand in an area with
hardly any vegetation, enough wind to move grains of sand and some kind
of obstacle to make the blowing sand lose its momentum and settle in a
new place</span>
Rate of Sulfur dioxide : 2730.44 mL/s
<h3>Further explanation </h3>
Graham's law: <em>the rate of effusion of a gas is inversely proportional to the square root of its molar masses or </em>
the effusion rates of two gases = the square root of the inverse of their molar masses:
![\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7Br_1%7D%7Br_2%7D%3D%5Csqrt%7B%5Cdfrac%7BM_2%7D%7BM_1%7D%20%7D)
or
![\rm M_1\times r_1^2=M_2\times r_2^2](https://tex.z-dn.net/?f=%5Crm%20M_1%5Ctimes%20r_1%5E2%3DM_2%5Ctimes%20r_2%5E2)
MW of N₂ = 28 g/mol
MW SO₂ = 64 g/mol
![\tt 28\times 79^2=64\times r_2^2\\\\r_2^2=\dfrac{28\times 79^2}{64}=2730.44~mL/s](https://tex.z-dn.net/?f=%5Ctt%2028%5Ctimes%2079%5E2%3D64%5Ctimes%20r_2%5E2%5C%5C%5C%5Cr_2%5E2%3D%5Cdfrac%7B28%5Ctimes%2079%5E2%7D%7B64%7D%3D2730.44~mL%2Fs)
Answer:
The amount of mass and matter in all the transformations of the clay ball will remain the same or constant
Explanation:
From the law of conservation of mass we have, for an enclosed system to and from which there is no transfer of matter or energy, mass cannot be created nor destroyed, and remains constant at the given value, but the matter which make up the mass can be changed into different forms
Therefore, the clay ball can be transformed into different shapes and will still posses the same initial mass before the transformation, provided there are no transfer of matter or energy from the clay ball system.