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sdas [7]
2 years ago
13

What takes place in organelles called chloroplasts

Chemistry
1 answer:
Vitek1552 [10]2 years ago
5 0
Photosynthesis takes place in the chloroplasts, that is why the chloroplasts is green. The function of this organelles is to create energy into sugar from the sunlight.
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Why is knowing the density of water important to us? Give a reasonable answer
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Measuring density is very important for many different industries because the density measurement will help determine the characteristics of a material, for example, whether the material will float or sink. Knowing the density of a material helps in determining the mass and volume of a material, all of which are extremely important measurements in all industries.

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8 0
1 year ago
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
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What did J.J. Thomson discover about the atom that changed the atomic model previously used?
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J.J. Thomson hypothesized and discovered that the atom was not the smallest unit of matter but that instead there were much smaller units. He discovered "sub-atomic particles" which make up atoms. The sub-atomic particle that Thomson discovered was the electron. He discovered this through a process of experiments testing cathode rays.
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In E. coli, the enzyme hexokinase catalyzes the reaction: Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Ke
kondor19780726 [428]

Answer:

Explanation:

Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Keq, is 7.8 x 102.

In the living E. coli cells,

[ATP] = 7.9 mM;

[ADP] = 1.04 mM,

[glucose] = 2 mM,

[glucose 6-phosphate] = 1 mM.

Determine if the reaction is at equilibrium. If the reaction is not at equilibrium, determine which side the reaction favors in living E. coli cells.

The reaction is given as

Glucose + ATP → glucose 6-phosphate + ADP

Now reaction quotient for given equation above is

q=\frac{[\text {glucose 6-phosphate}][ADP]}{[Glucose][ATP]}

q=\frac{(1mm)\times (1.04 mm)}{(7.9mm)\times (2mm)} \\\\=6.582\times 10^{-2}

so,

q ⇒ following this criteria the reaction will go towards the right direction ( that is forward reaction is favorable  until q = Keq

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