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sesenic [268]
3 years ago
6

Balance the equation below and use it to answer this question:

Chemistry
1 answer:
Svet_ta [14]3 years ago
8 0

Answer:

2H2 + O2 -----> 2H2O

Not sure about the second question though.

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A chemist adds 0.50 mol acetic acid (CH3CO2H) to a solution. What else should be added to maximize the buffering effect?
musickatia [10]
.50,mol sodium acetate (NaCH3CO2) should be added to maximize the buffering effect.
<span>
</span><span>A </span>buffering effect<span> is a process in which a psychosocial resource reduces the impact of life stress on psychological well-being. Having such a resource contributes to adjustment because persons are less affected by negative life events.</span>
6 0
4 years ago
Read 2 more answers
Estimate ΔG°rxn for the following reaction at 775 K. 2Hg(g) + O2(g) → 2HgO(s) ΔH°= -304.2 kJ; ΔS° = -414.2 J/K
hichkok12 [17]

Answer:

\Delta G^0_{rxn}=16.81kJ

Explanation:

Hello!

In this case, since the Gibbs free energy of any process is related with the enthalpy change, temperature and entropy change as shown below:

\Delta G^0=\Delta H^0-T\Delta S^0

For a chemical reaction it is simply modified to:

\Delta G^0_{rxn}=\Delta H^0_{rxn}-T\Delta S^0_{rxn}

Thus, since the enthalpy of reaction is given as -304.2 kJ and the entropy as -414.2 J/K (-0.4142 kJ/K), at 775 K the Gibbs free energy of reaction turns out:

\Delta G^0_{rxn}=-304kJ-775K*(-0.4142\frac{kJ}{K} )\\\\\Delta G^0_{rxn}=16.81kJ

Whose result means this is a nonspontaneous reaction.

Best regards!

3 0
3 years ago
1. Determine the number of significant figures in the following values:
denpristay [2]

Answer:

The zero to the left of a decimal value less than 1 is not significant.All trailing zeros that are placeholders are not significant.Zeros between non-zero numbers are significant.All non-zero numbers are significant.

7 0
2 years ago
How many grams of O2(g) are needed to completely burn 46.0 g C3H8(g)?
Veronika [31]

Answer:

167,3 grams of O2 (g)

Explanation:

According to the following balanced equation:

C3H8 + 5 02 ---> 3 CO2 + 4 H20

We calculate the mass of the moles:

5 mol O2 = 16grams/mol x2x 5= 160 grams/mol

1 mol C3H8= 3 x12 grams/mol + 8 x 1 gram/mol= 44 grams/mol

If 44 grams C3H8 react with--------- 160 grams O2

46 gramsC3H8 react with    --------X = (46x160)/44 =167, 3 grams O2

8 0
4 years ago
the force of gravity between a plant and its moon is 371 N. if the planet has a mass of 4*1022kg and the moon has a mass of 5*10
pentagon [3]

Answer:

59977533.98m

Explanation:

7 0
3 years ago
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