The volume of the gas is 180.26 L, if there are 63.5 mol of an ideal gas at 9.11 atm at 42.80 °C.
Applying the ideal gas law PV= nRT
After rearranging the aforementioned expression, the volume might then be found as: V= n R T/ P.
Consequently, V= 63.5 mol, 0.0821, 315 K, and 9.11 atm equal 180.26 L.
<h3>How is the ideal gas equation defined?</h3>
The ideal gas equation is PV = nRT. In this equation, P denotes the ideal gas's pressure, V its volume, n its total amount, expressed in moles, and R its resistance for the universal gas constant, and T for temperature.
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Answer:
Explanation:
You need the conversion factor to convert the value of 12.33 kPa to milimiters of mercury, mmHg.
The converstion factors are looked at tables, which today you can find in internet.
Since the conversions between kPa and atm and between atm and mmHg are more widely known, I will show the conversion using those relations:
⇒ 101.325 kPa = 760 mmHg
Then, dividing both sides by 101.325 kPa you get the conversion factor:
- 1 = 760 mmHg / 101.325 kPa
Now, multiply 12.33 kPa by that conversion factor:
- 12.33 kPa × 760 mmHg / 101.325 kPa = 92.48 mmHg ← answer
3 major groups are metals,metalloids, and the non-metals.
Answer:
Both student have same percent error.
Explanation:
Given data:
Actual mass of object = 0.54 g
Measured value by one student = 0.59 g
Measured value by second student = 0.49 g
Percent error = ?
Solution:
Formula
Percent error = (measured value - actual value / actual value) × 100
Percent error of first student:
percent error = (0.59 g - 0.54 / 0.54 ) ×100
percent error = 9.3 %
Percent error of second student:
Percent error = (0.49 g - 0.54 / 0.54 ) ×100
Percent error = - 9.3 %
Both student have same percent error. The only difference is that first student measure the greater value then actual value and second student measure the less value then actual, however difference was same and gives same percent error.
A + B = Products
This is the correct mechanism.
