Answer: B. 11%
Step-by-step explanation:
Let A = Event that students eat breakfast in the morning.
B= Event that students floss their teeth.
We are given P(A)=57%=0.57
P(B)=80%=0.80
P(A∩B) = 46% =0.46
Now, the probability that a student from this class eats break feast but does not floss their teeth :-
Hence, the probability that a student from this class eats break feast but does not floss their teeth= 11%
To solve this problem you must apply the proccedure shown below:
1. You have the following system of equation:
2. As you can see, you can cancel out the variable , because it has equal coefficient with different signs at both equations. Then, if you add both equations, you obtain:
3. Let's substitute the value obtained into the second equation to calculate the other variable:
The answer is: (6,-6).
Answer:
Step-by-step explanation: