If your unemployment rate is high, that means you're making less money in all. If many people are without jobs, that means your labor force is also weak. Your employers will make a lot of cutbacks.
Answer:
a-The present value of revenue in the first year is $61,085.92.
b-The total time it would take to pay for its price is 2.44 years of 29.33 months.
Explanation:
a-
Let the function of the revenue earned is given as
![S(t)=\left \{ {{66000t+38000} {\ \ 0The present value is given as [tex]PV=\int\limits^a_b {S(t)e^{-rt}} \, dt](https://tex.z-dn.net/?f=S%28t%29%3D%5Cleft%20%5C%7B%20%7B%7B66000t%2B38000%7D%20%7B%5C%20%5C%200%3C%2Fp%3E%3Cp%3EThe%20present%20value%20is%20given%20as%20%3C%2Fp%3E%3Cp%3E%5Btex%5DPV%3D%5Cint%5Climits%5Ea_b%20%7BS%28t%29e%5E%7B-rt%7D%7D%20%5C%2C%20dt)
Here
- a and b are the limits of integral which are 0 and 1 respectively
- r is the rate of interest which is 5% or 0.05
- S(t) is the function of value which is
![S(t)=\left \{ {{66000t+38000} {\ \ 0So the equation becomes[tex]PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t+38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t)e^{-0.05t}} \, dt+\int\limits^{0.5}_0 {(38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=8113.7805+18764.4669+34207.6751\\PV=61085.9225](https://tex.z-dn.net/?f=S%28t%29%3D%5Cleft%20%5C%7B%20%7B%7B66000t%2B38000%7D%20%7B%5C%20%5C%200%3C%2Fli%3E%3C%2Ful%3E%3Cp%3ESo%20the%20equation%20becomes%3C%2Fp%3E%3Cp%3E%5Btex%5DPV%3D%5Cint%5Climits%5E0_1%20%7BS%28t%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2866000t%2B38000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B1%7D_%7B0.5%7D%7B%2871000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2866000t%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2838000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B1%7D_%7B0.5%7D%7B%2871000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D8113.7805%2B18764.4669%2B34207.6751%5C%5CPV%3D61085.9225)
So the present value of revenue in the first year is $61,085.92.
b-
The time in which the machine pays for itself is given as
The present value is set equal to the value of machine which is given as
$160,000 so the equation becomes:
So the total time it would take to pay for its price is 2.44 years of 29.33 months.
The amount to be recorded as depreciation expense on December 31, 2021, is (B) $9,590.
<h3>
What is depreciation expense?</h3>
- Depreciation expense is the cost of a depreciated asset for a specific period, and it reveals how much of the asset's value was used up in that year.
- Accumulated depreciation is the entire amount of depreciation expense given to an asset since it was placed in service.
- A business spends $84,000 on new display racks with a useful life of 7 years (84 months) and no residual value.
- The corporation would most likely choose a straight-line depreciation technique, which would result in a $1,000 monthly depreciation expenditure ($84,000/84 months = $1,000 per month).
The straight-line technique of calculating depreciation expense is given below:
- = (Original cost - salvage value) ÷ (useful life)
- = ($173,000 - $8,600) ÷ (10 years)
- = ($164,400,000) ÷ (10 years)
- = $16,440
In this method, the depreciation is the same for all the remaining useful life.
Now for the 7 months, the depreciation expense would be:
- = $16,440 × 7 months÷ 12 months
- = $9,590
Therefore, the amount to be recorded as depreciation expense on December 31, 2021, is (B) $9,590.
Know more about depreciation expenses here:
brainly.com/question/25785586
#SPJ4
The correct question is given below:
A company purchased factory equipment on June 1, 2021, for $173000. It is estimated that the equipment will have a $8600 salvage value at the end of its 10-year useful life. Using the straight-line method of depreciation, the amount to be recorded as depreciation expense at December 31, 2021, is ______.
(A) $16440.
(B)$9590.
(C)$8220.
(D)$6850.
