Hydrophilic substances will dissolve better in water than hydrophobic substances. A substance that is hydrophilic is water loving or easily dissolved in water. Molecules of these substances form ionic bonds with the water molecules. Hydrophilic substances include alcohols. Hydrophobic substances repel water and do not mix.
Answer:
The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas.
Explanation:
Bedrock is used in the construction of structures, the topsoil is important for the production of crops and the loss of fertile soil is known as desertification.
<h3>Bedrocks, topsoil, and desertification</h3>
- Bedrocks are underlining rocks below soils. They are useful in construction works such as buildings, bridges, etc.
- Topsoils are the topmost portions of soils. They are usually rich in humus and organic matter and are therefore very good for agricultural crop production.
- Desertification is simply the loss of fertile soils and their transformation to barren, unproductive lands. Topsoils are lost and soils are rendered unsuitable for agriculture.
More on desertification can be found here: brainly.com/question/24255548
Answer:
Acetone and water is immiscible
Acetone and hexane is miscible
Explanation:
Acetone with the chemical formula (CH3)2CO, is a nonpolar organic liquid that will mix easily. Hexane, an aliphatic hydrocarbon with 6 carbon atoms represented as C6H14 is also nonpolar. Thus, acetone and hexane would mixed completely to form a clear solution in the test tube.
On the other hand, acetone and water is immiscible (do not mix) since water, H2O, is a polar compound. And polar compounds do not react or dissolve nonpolar compounds (acetone). Usually, a mixture of acetone and water will be seen to form two distinct layers in the test tube.
Answer:
The rate law is [B]
Explanation:
In Trials 1 and 2, the concentration of B changes and A is the same so you can see how changes in B affect the rate. In this case, 0.300/0.150=2 and 7.11 x 10^-4 / 3.56 x 10^-4= 2. Since there 2^1=2, we can say that the reaction order of B is 1.
Similarly, if we look at trials 2 and 3, the concentration of B is constant, while A is changing. In this case, the rate has not changed at all with a change in concentration of A, so this means that A has 0 order.
Therefore, the rate law is just [B].
