Answer:
130.4 grams of sucrose, would be needed to dissolve in 500 g of water.
Explanation:
Colligative property of boiling point elevation:
ΔT = Kb . m . i
In this case, i = 1 (sucrose is non electrolytic)
ΔT = Kb . m
0.39°C = 0.512°C/m . m
0.39°C /0.512 m/°C = m
0.762 m (molality means that this moles, are in 1kg of solvent)
If in 1kg of solvent, we have 0.712 moles of sucrose, in 500 g, which is the half, we should have, the hallf of moles, 0.381 moles
Molar mass sucrose = 342.30 g/m
Molar mass . moles = mass
342.30 g/m . 0.381 m = 130.4 g
Most definitely! Consider bacteria in a petri dish. Organisms need nutrition to survive, and when overcrowding is an issue (which by definition means that there is an insufficient amount of space/resources for the current population), organisms cannot survive and reproduce.
Answer:
Sodium atoms due to being smaller in size have high ionization energy and thus, it can't lose electrons easily and is more stable and less reactive. ... Hence, from this it is clear that sodium is less reactive than potassium.
Explanation:
For this question, we can use relations for pH and pOH. We calculate as follows:
pOH = -log [OH-]
pOH = -log [<span>1.83x10^-7 M]
pOH = 6.74
pH + pOH = 14
pH = 14 - 6.74
pH = 7.26
pH = -log [H3O+]
7.26 = -log[H3O+]
[H3O+] = 5.46 x 10^-8 M
Hope this answers the question. Have a nice day.</span>