Answer:
A description of the experiment the chemicals were used for.
Explanation:
A chemical waste label is required to provide information about any hazardous waste present in the container. Some details are mandatory to mention of the chemical waste label to prevent any accident while doing the experiment, that includes:
- Chemical compound's name present in the container.
- Composition and physical state of the waste.
- Hazardous properties of the waste.
- The date of manufacturing.
- Amount of chemical compounds filled in the container.
A chemical waste label does not mention or describe the experiment for which the chemicals were used for, scientists, teacher or students should have knowledge of the chemical composition by reading their names and evaluate themselves on which chemical should be used for which experiment.
Hence, the correct answer is "A description of the experiment the chemicals were used for."
The average speed of the horse for the entire motion is 66.67 m/s.
The given parameters;
- <em>distance traveled by the horse, d = 1 km = 1,000 m</em>
- <em>time of motion of the horse, t = 15 s</em>
The average speed of the horse is calculated by dividing the total distance traveled by the horse by the time of motion.
The average speed of the horse is calculated as follows;
Thus, the average speed of the horse for the entire motion is 66.67 m/s.
Learn more here: brainly.com/question/17289046
Answer:
0.00268 M
Explanation:
To find the new molarity, you need to (1) find the moles of CuSO₄ (via the molarity equation using the beginning molarity and volume) and then (2) find the new molarity (using the moles and combined volume). Your final answer should have 3 sig figs to match the given values.
<u>Step 1:</u>
3.00 mL / 1,000 = 0.00300 L
Molarity = moles / volume (L)
0.0250 M = moles / 0.00300 L
(0.0250 M) x (0.00300 L) = moles
7.50 x 10⁻⁵ = moles
<u>Step 2:</u>
25.0 mL / 1,000 = 0.0250 L
0.0250 L + 0.00300 L = 0.0280 L
Molarity = moles / volume (L)
Molarity = (7.50 x 10⁻⁵ moles) / (0.0280 L)
Molarity = 0.00268 M