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Savatey [412]
2 years ago
5

Can you please help with equations tables and graphs

Mathematics
1 answer:
Oxana [17]2 years ago
7 0
I will be able to answer this question, if it wasn't sideways
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Planes X and Y and points C, D, E, and F are shown.
jekas [21]

Answer: Maybe B

Step-by-step explanation:

6 0
2 years ago
Sandy plans on making 100 cookies that are the same size from 212.7 ounces of dough. How many ounces of dough should make up eac
Hitman42 [59]

Answer: 2.127

Step-by-step explanation:

For this problem, we have to divide the number 212.7 by 100 cookies.

212.7 ÷ 100 = 2.127

So, each cookie will require 2.127 ounces of dough.

5 0
3 years ago
Read 2 more answers
I need serious answers ppl keep putting those links
ohaa [14]

Answer:

Roman

Step-by-step explanation:

An easy way to solve this is looking at whether the line has a positive or negative slope. We read graphs from left to right so <u>if the line is increasing from left to right, it has a positive slope while a line decreasing from left to right has a negative slope</u>. Since the line shown is decreasing from left to right, it will have a negative slope and Roman is the only one out of the two that shows a negative slope. To check to see if he's correct, we can check the y-intercept. The y-intercept of the line is 8 and Roman also has 8 written in the expression. Hence, meaning Roman is correct.

Best of Luck!

7 0
2 years ago
PLEASE HELP
lilavasa [31]

Those two functions just miss each other so there are no real solutions.  Every polynomial with complex coefficients has complex solutions.

2x^2 + 2 = 3x

2x^2 - 3x = -2

2( x^2 - \frac 3 2 x) = -2

x^2 - \frac 3 2 x = -1

x^2- \frac 3 2 x+ (\frac 3 4)^2= -1 + (\frac 3 4 )^2

(x - \frac 3 4)^2 = -\frac 7{16}

x - \frac 3 4 = \pm \sqrt{ -\frac 7{16}}

x = \frac 3 4 \pm \frac i 4 \sqrt{7}

x = \frac 1 4(3 \pm i \sqrt{7})


4 0
2 years ago
10. The value of the 8th term is 78.
Yuri [45]

Answer: The answer is 88

Step-by-step explanation: It is recursive because you can add 78+10=88

5 0
3 years ago
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