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Oksana_A [137]
3 years ago
8

2. The general equation of a plane is Ax + By + Cz = D, where A, B, C, and D are real numbers and A is nonnegative. Find the equ

ation of the plane containing the points (3, 0, 0), (0, 8, 0), and (0, 0, 6). Show each step of your process. Then graph the plane.

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0

Answer:

The standard equation is 8x+3y+4z= -24.

Step-by-step explanation:

Given : The general equation of a plane is Ax + By + Cz = D, where A, B, C, and D are real numbers and A is non negative.

We have to find the equation of the plane containing the points (3, 0, 0), (0, 8, 0), and (0, 0, 6).

If given coordinates of three points A(x_1, y_1, z_1), B(x_2, y_2, z_2),C(x_3, y_3, z_3) lying on a plane are defined then the plane equation can be found using the formula,

\left[\begin{array}{ccc}x - x_1&y-y_1&z-z_1\\x_2 - x_1&y_2-y_1&z_2-z_1\\x_3 - x_1&y_3-y_1&z_3-z_1\end{array}\right]=0

For the given coordinates, A(3, 0, 0), B(0, 8, 0), and C(0, 0, 6)

Substitute, we have,

\begin{pmatrix}x-3&y-0&z-0\\ \:0-3&8-0&0-0\\ \:0-3&0-0&6-0\end{pmatrix}=0

Solving further, we get,

\begin{pmatrix}x-3&y&z\\ \:-3&8&0\\ \:-3&0&6\end{pmatrix}=0

Evaluate along row !, we get,

(x-3)(8\cdot6-0) -y((-3)\cdot6-0)+z(0-8\cdot (-3))

We get,

48(x-3)+18y+24z=0

Simplify , we get,

8x+3y+4z -24 = 0

Thus, the standard equation is 8x+3y+4z= -24

 

     

lidiya [134]3 years ago
3 0
Z=6-(3/4)y-2x 
<span>z+(3/4)y+2x=6 </span>

<span>By connecting the three points in the graph, Got this equation by isolating each plane to figure it out. </span>
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