Using proportions and the information given, it is found that:
- The class width is of 14.375.
- The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
- The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.
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- Minimum value is 19.
- Maximum value is of 134.
- There are 8 classes.
- The classes are all of equal width, thus the width is of:

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The intervals will be of:
19 - 33.375
33.375 - 47.750
47.750 - 62.125
62.125 - 76.500
76.500 - 90.875
90.875 - 105.250
105.250 - 119.625
119.625 - 134.
- The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
- The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.
A similar problem is given at brainly.com/question/16631975
So,
Obviously, the car will travel 70 miles in one hour. So after one hour, the car will have traveled 70 miles. That leaves 18 miles.
The time it will take for the car to go another 18 miles will be 18 divided by 70.

Simplify.



Divide.
≈ 0.25714
So a car traveling at 70 mph will take approximately 1.25714 hours or 1.26 hours to travel 88 miles.
1,002,003 rounded to the ten thousand place is 1,000,000
Width = x
Length = 3x
Perimeter = x + x + 3x + 3x = 8x
He walked 3 rounds
3 x 8x = 24x
Total distance walked = 5280 feet
24x = 5280
x = 220
Shortest side is 220 feet
Use PEMDAS:
P arenthesis
E xponents
M ultiplication
D ivision
A dd
S ubstract
Paranthesis and Exponents
(20 / 2^2 * 5 / 5) = 5
Multiplication
5*8= 40
Division
10 / 40 = 0.25
Subtraction
0.25 - 2 = −1.75
Therefore,
The answer is -1.75