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Katyanochek1 [597]
3 years ago
7

If g(x)=5x-3 and h(x)=square roto of x, find (g•h) (4)

Mathematics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

(goh) (4) = 7

Step-by-step explanation:

(goh) (x) = g(h(x))

Plug in

g(h(x)) = 5(√x) - 3

if x = 4 then

g(h(4)) = 5(√4) - 3

g(h(4)) = 5(2) - 3

g(h(4)) = 10 - 3

g(h(4)) = 7

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</span><span>Explanation:
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Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

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If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
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