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3 years ago

What is the product?

Mathematics

2 answers:

bonufazy [111]3 years ago

4 0

B. 15r^2 - 8 @*×£×*×(

vaieri [72.5K]3 years ago

4 0

Answer:

$15r^2-14r-8$

Step-by-step explanation:

The given expression is $(5r+2)(3r-4)$

Using the FOIL to multiply.

$5r\cdot3r+2\cdot3r-5r\cdot4-2\cdot4$

Now, on multiplying

$15r^2+6r-20r-8$

Combine the like terms

$15r^2-14r-8$

Therefore, D is the correct option.

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Please help! I am supposed to write a recursive and an explicit function for the geometric sequence but this one is really frust

makkiz [27]

Step-by-step explanation:

Initially, there's only 1 letter.

Tania sends the letter to 4 friends.

Each friend sends a letter to 4 more friends (4 × 4 = 16).

Each of those friends sends to 4 more friends (16 × 4 = 64).

The pattern is 1, 4, 16, 64, etc.

This is a geometric sequence. The first term is 1 and each term is 4 times the previous term.

a₁ = 1

aₙ = 4 aₙ₋₁

The explicit formula is:

aₙ = 1 (4)ⁿ⁻¹

7 0

3 years ago

A computer rounded the number 129. 257 to the nearest hundredth what is this number rounded to the nearest hundredth

Ipatiy [6.2K]

129.26 because 7 is over 5

6 0

3 years ago

Nuetrik [128]

Answer:

Distance LM = 5.20 unit (Approx.)

Step-by-step explanation:

Given coordinates;

L(1, 4, 7) and M(2, 9, 8)

Find:

Distance LM

Computation:

Distance between three-dimensional plane = √(x2 - x1)² + (y2 - y1)² + (z2 - z1)²

Distance LM = √(2 - 1)² + (9 - 4)² + (8 - 7)²

Distance LM = √(1)² + (5)² + (1)²

Distance LM = √1 + 25 + 1

Distance LM = √27

Distance LM = 3√3 unit

Distance LM = 3(1.732)

Distance LM = 5.196

Distance LM = 5.20 unit (Approx.)

5 0

3 years ago

A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the

Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

$P(A) = 0.90*0.03 + 0.1*0.97 = 0.124$

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

$P(A \cap B) = 0.9*0.03 = 0.027$

What is the conditional probability that she does, in fact, have the disease

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177$

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0

3 years ago

Janice deposited $750 in a savings account that earns 3.5% simple interest. How much interest has Janice earned by the end of th

Ronch [10]

Janice deposited $750 and a savings account earns 3.5% simple interest.
r = 3.5% = 0.035
I = $750 * 0.035
I = $26.25
Answer:
Janice has earned
D ) $26.25

8 0

3 years ago