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3 years ago

Math question thanks

Mathematics

2 answers:

dimulka [17.4K]3 years ago

3 0

Using product and quotient property:

log x + log y can be displayed as log xy

Because we're subtracting 2 log z we can use the power property to rewrite this as log z^2

Now, using quotient property we can display this expression as:

Tju [1.3M]3 years ago

3 0

Using product and quotient property:

log x + log y can be displayed as log xy

Because we're subtracting 2 log z we can use the power property to rewrite this as log z^2

Now, using quotient property we can display this expression as:

log xy/z^2

Read more on Brainly.com - brainly.com/question/11716592#readmore

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Help me in both please it’s a test and i need help

nataly862011 [7]

1. -2x + 3y + 5

A. -x + -x + y + y + y + 1 + 1 + 1 + 1 + 1

B. -x + -x + 2y + y + 4 + 1

D. -5x + 3x + 4y - y + 4 + 1

2. -$40 + 100 = $60 - $50 = $10

Cindy currently has $10 left in her bank account.

5 0

3 years ago

An arithmetic sequence has a1 = 22 and a8 = 43. Find a15.

brilliants [131]

The 15th term of the arithmetic sequence $a_{15} = 64$

Option B is correct

The nth term of an arithmetic sequence is given as:

$a_{n} = a + (n - 1)d$

The first value, a = 22

$a_8 = a+(8 - 1)d\\a_8 = a + 7d$

Since $a_8 = 43$

$43 = 22 + 7d\\7d = 43 - 22\\7d = 21\\d = \frac{21}{7}\\d = 3$

The common difference, d = 3

$a_{15}= a + (15-1)d\\a_{15} = a + 14d\\a_{15} = 22 + 14(3)\\a_{15} = 22 + 42\\a_{15} = 64$

The 15th term of the arithmetic sequence = 64

Learn more here: brainly.com/question/24072079

4 0

2 years ago

The Gophers won 2/3 of their games. The Rattlers

ZanzabumX [31]

Answer:

Step-by-step explanation:

The silmutenous equations

2/3x + 1/2y = 56

X=y

4 0

3 years ago

The State Board of Education has $2,183 to buy new calculators. If each calculator costs $37, how many calculators can the board

Tema [17]

Answer:

Step-by-step explanation:

They could buy 59

You solve this by dividing the total amount of money ($2183) by the other amount ($37) which is 59

5 0

3 years ago

A box of 42 chocolates contains milk and dark chocolates in the ratio of 3:4. How many chocolates of each type there are?

Elza [17]

<h2>Answer:The number of milk chocolates are 18 and the number of dark chocolates are 24.</h2>

Step-by-step explanation:

Let the number of milk chocolates be $m$ .

Let the number of dark chocolates be $d$ .

Given that the box contains the milk and dark chocolates in the ratio $3:4$ .

So, $\frac{m}{d}=\frac{3}{4}$ ...(i)

Given that the total number of chocolates are $42$ .

So, $m+d=42$ . ...(ii)

Using (i) and (ii),

$m+\frac{4}{3}m=42$

$\frac{7}{3}m=42$

$m=18$

$d=\frac{4}{3}m=\frac{4}{3}\times 18=24$

So,the number of milk chocolates are $18$ and the number of dark chocolates are $24$ .

4 0

3 years ago