The question is incomplete, here is the complete question:
An aqueous solution at 25°C has a
concentration of
. Calculate the
concentration. Be sure your answer has the correct number of significant digits.
<u>Answer:</u> The hydroxide ion concentration of the solution is 
<u>Explanation:</u>
To calculate the pH of the solution, we use the equation:
![pH=-\log[H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH_3O%5E%2B%5D)
We are given:
![[H_3O^+]=8.8\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D8.8%5Ctimes%2010%5E%7B-12%7DM)
Putting values in above equation, we get:

To calculate the hydroxide ion concentration, we first calculate pOH of the solution, which is:
pH + pOH = 14

To calculate hydroxide ion concentration of the solution, we use the equation:
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
We are given:
pOH = 2.95
Putting values in above equation, we get:
![2.95=-\log[OH^-]](https://tex.z-dn.net/?f=2.95%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=10^{-2.95}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-2.95%7D)
![[OH^-]=1.12\times 10^{-3}M=0.1\times 10^{-2}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.12%5Ctimes%2010%5E%7B-3%7DM%3D0.1%5Ctimes%2010%5E%7B-2%7DM)
Hence, the hydroxide ion concentration of the solution is 