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vladimir2022 [97]
3 years ago
10

What would be the temperature change if 3.0 g of water absorbed 15 J of heat? Specific Heat capacity of water= 4.18 J/gºC

Chemistry
1 answer:
kati45 [8]3 years ago
3 0
Not sure but I think it’s B try it out and double check it
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The substance's mass is 450.0 grams, the specific heat is 1.264 J/g°C, and the  change in temperature is 7.1 °C.

m= 450.0 \ g \\c= 1.264 \ J/g \textdegree C\\\Delta T= 7.1 \ \textdegree C

Substitute the values into the formula.

q= (450.0 \ g)(1.264 \ J/g \textdegree C)(7.1 \ \textdegree C)

Multiply the first 2 values together. The grams will cancel out.

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