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2 years ago

What is (4x+-7)(2x+-9)

Mathematics

1 answer:

uysha [10]2 years ago

8 0

Answer:x=1

Step-by-step explanation:(4x+-7)=(2x+-9)

We move all terms to the left:

(4x+-7)-((2x+-9))=0

We add all the numbers together, and all the variables

(4x-7)-((2x-9))=0

We get rid of parentheses

4x-((2x-9))-7=0

We calculate terms in parentheses: -((2x-9)), so:

(2x-9)

We get rid of parentheses

2x-9

Back to the equation:

-(2x-9)

We get rid of parentheses

4x-2x+9-7=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

(4x+-7)=(2x+-9)

We move all terms to the left:

(4x+-7)-((2x+-9))=0

We add all the numbers together, and all the variables

(4x-7)-((2x-9))=0

We get rid of parentheses

4x-((2x-9))-7=0

We calculate terms in parentheses: -((2x-9)), so:

(2x-9)

We get rid of parentheses

2x-9

Back to the equation:

-(2x-9)

We get rid of parentheses

4x-2x+9-7=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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