During a 400-m race, a runner crosses the 100 m mark with a velocity of 12 m/s. What would be her final position if she maintain
ed her velocity for another 10 seconds (in m)?
2 answers:
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10.92N
Explanation:
Given parameters:
Mass of truck = 2.964kg
Velocity of truck = 7m/s
Time taken = 1.9s
Unknown:
Average force on the car = ?
Solution:
According to newton's third law of motion "action and reaction are equal and opposite".
The force with which the truck struck the fence is the same as the force the fence acted on the truck with but in another direction.
From newton's second law:
Force = mass x acceleration
We know that acceleration is the change in velocity with time;
acceleration =
Force = mass x
Force = = 10.92N
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1. -23.2 J
The gravitational potential energy of the ball is given by
where
m = 1.1 kg is the mass of the ball
g = 9.8 m/s^2 is the acceleration of gravity
h is the height of the ball, relative to the reference point chosen
In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is
h = -2.16 m
And the gravitational potential energy is
2. 41.1 J
Again, the gravitational potential energy of the ball is given by
In this part of the problem, the reference point is the floor.
The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:
h = 5.97 m - 2.16 m = 3.81 m
And so the gravitational potential energy of the ball relative to the floor is
3. 0 J
As before, the gravitational potential energy of the ball is given by
Here the reference point is a point at the same elevation of the ball.
This means that the heigth of the ball relative to that point is zero:
h = 0 m
And so the gravitational potential energy is